MatinSAR
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The discussion revolves around finding the electric field due to an electric dipole at the origin. Participants are exploring the mathematical expressions and derivatives involved in this context.
Several participants are engaged in exploring the mathematical details, with some providing partial expressions and seeking confirmation on their reasoning. There is an ongoing exchange of ideas without a clear consensus on the final expression.
Some participants express uncertainty regarding the final answer and the relationship between the derived expressions and the electric field. There are indications of confusion about specific terms and their implications in the context of the problem.
Then it is equal to ##Pr^{-3}##, Am I right?!kuruman said:Just expand the dot product and ##\vec r## then take derivatives.$$(\vec p\cdot \vec{\nabla})\vec r = \left(p_x\frac{\partial}{\partial x}+p_y\frac{\partial}{\partial y}+p_z\frac{\partial}{\partial z}\right)(x~\hat x+y~\hat y+z~\hat z)$$
kuruman said:Show me the math.
Yes. What is your final answer when you put it all together?MatinSAR said:I have used:
##p_x\frac{\partial}{\partial x}y=0##
##p_x\frac{\partial}{\partial x}z=0##
##p_y\frac{\partial}{\partial y}x=0##
##p_y\frac{\partial}{\partial y}z=0##
##p_z\frac{\partial}{\partial z}x=0##
##p_z\frac{\partial}{\partial z}y=0##
##p_x\frac{\partial}{\partial x}x=p_x##
##p_y\frac{\partial}{\partial y}y=p_y##
##p_z\frac{\partial}{\partial z}z=p_z##
##\vec P## , I guess.kuruman said:Yes. What is your final answer when you put it all together?
I am trying to solve ... I will send the work.kuruman said:Sorry, not that. I meant putting together the final expression ##\vec E=-\vec{\nabla}\psi=?##
Thanks a lot! Have a good day.kuruman said:That's it. Good job!