Find the Electric field due to an electric dipole at the origin

AI Thread Summary
The discussion revolves around calculating the electric field due to an electric dipole at the origin. Participants are working through the mathematical derivation, focusing on expanding the dot product and taking derivatives of the position vector. Key expressions are discussed, including the relationship between the dipole moment and the resulting electric field. The final expression for the electric field is confirmed, with participants expressing gratitude for assistance. The conversation concludes positively, emphasizing successful problem-solving.
MatinSAR
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Homework Statement
Find electric field due to dipole at any point using ##\vec E=-\nabla \phi##.
Relevant Equations
##\vec E=-\nabla \phi##
Question :

1699296919913.png


I have tried to solve but I struggle with this part:
1699297291071.png

Any help would be appreciated.
 

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Just expand the dot product and ##\vec r## then take derivatives.$$(\vec p\cdot \vec{\nabla})\vec r = \left(p_x\frac{\partial}{\partial x}+p_y\frac{\partial}{\partial y}+p_z\frac{\partial}{\partial z}\right)(x~\hat x+y~\hat y+z~\hat z)$$
 
kuruman said:
Just expand the dot product and ##\vec r## then take derivatives.$$(\vec p\cdot \vec{\nabla})\vec r = \left(p_x\frac{\partial}{\partial x}+p_y\frac{\partial}{\partial y}+p_z\frac{\partial}{\partial z}\right)(x~\hat x+y~\hat y+z~\hat z)$$
Then it is equal to ##Pr^{-3}##, Am I right?!
 
Show me the math.
 
kuruman said:
Show me the math.
1699298882251.png

Sorry that ##r^{-3}## was related to another part.
 
I have used:
##p_x\frac{\partial}{\partial x}y=0##
##p_x\frac{\partial}{\partial x}z=0##
##p_y\frac{\partial}{\partial y}x=0##
##p_y\frac{\partial}{\partial y}z=0##
##p_z\frac{\partial}{\partial z}x=0##
##p_z\frac{\partial}{\partial z}y=0##

##p_x\frac{\partial}{\partial x}x=p_x##
##p_y\frac{\partial}{\partial y}y=p_y##
##p_z\frac{\partial}{\partial z}z=p_z##
 
MatinSAR said:
I have used:
##p_x\frac{\partial}{\partial x}y=0##
##p_x\frac{\partial}{\partial x}z=0##
##p_y\frac{\partial}{\partial y}x=0##
##p_y\frac{\partial}{\partial y}z=0##
##p_z\frac{\partial}{\partial z}x=0##
##p_z\frac{\partial}{\partial z}y=0##

##p_x\frac{\partial}{\partial x}x=p_x##
##p_y\frac{\partial}{\partial y}y=p_y##
##p_z\frac{\partial}{\partial z}z=p_z##
Yes. What is your final answer when you put it all together?
 
kuruman said:
Yes. What is your final answer when you put it all together?
##\vec P## , I guess.
 
Sorry, not that. I meant putting together the final expression ##\vec E=-\vec{\nabla}\psi=?##
 
  • #10
kuruman said:
Sorry, not that. I meant putting together the final expression ##\vec E=-\vec{\nabla}\psi=?##
I am trying to solve ... I will send the work.

Thanks again for your help Prof.Kuruman🙏.
 
  • #11
  • #12
That's it. Good job!
 
  • #13
kuruman said:
That's it. Good job!
Thanks a lot! Have a good day.
 
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