Find the electric field of a square at a given point?

Click For Summary

Homework Help Overview

The problem involves calculating the electric field at a specific point (Point A) in relation to two equal charges placed at the corners of a square. The context is within electrostatics, focusing on vector addition of electric fields generated by point charges.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of electric fields using a formula and the importance of vector addition in determining the resultant electric field. Questions arise regarding the reasoning behind taking differences versus summing contributions from each charge.

Discussion Status

Participants are engaging in clarifying the method for calculating the electric field, with some guidance provided on the necessity of treating electric fields as vectors. There is acknowledgment of the charges being of the same sign, which influences how their contributions are combined.

Contextual Notes

There is an emphasis on understanding vector addition in the context of electric fields, and participants are exploring the implications of charge signs on the calculations. The original poster's approach is being critically examined, highlighting the need for clarity in vector operations.

awilliam_3
Messages
7
Reaction score
0

Homework Statement



Two tiny objects with equal charges of 6.00uC are placed at the two lower corners of a square with sides of 0.580m.

When facing the square, Point A is the top left corner. Point B is in the top middle. Point C is dead center inside the square.

Find the electric field at Point A, the upper left corner.


Homework Equations



E = K [q1 / d^2]


The Attempt at a Solution



Calculated E1 & E2 using above formula and givens, then took the difference to determine the electric field in N/C.
 
Physics news on Phys.org
awilliam_3 said:
Calculated E1 & E2 using above formula and givens, then took the difference to determine the electric field in N/C.
Why did you take the difference? Instead, add the field contribution from each charge, remembering that the field is a vector and must be added as such.
 
welcome to pf!

hi awilliam_3! welcome to pf! :smile:
awilliam_3 said:
Calculated E1 & E2 using above formula and givens, then took the difference to determine the electric field in N/C.

(are the charges the same sign, or opposite sign? if they're opposite, then yes, you subtract)

you can't just add (or subtract) the magnitudes, you have to add (or subtract) the forces as vectors :wink:
 
Doc Al said:
Why did you take the difference? Instead, add the field contribution from each charge, remembering that the field is a vector and must be added as such.

Ah, I see. Thank you.
 


tiny-tim said:
hi awilliam_3! welcome to pf! :smile:


(are the charges the same sign, or opposite sign? if they're opposite, then yes, you subtract)

you can't just add (or subtract) the magnitudes, you have to add (or subtract) the forces as vectors :wink:

They are indeed the same sign. Great tip, thank you!
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 68 ·
3
Replies
68
Views
8K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 23 ·
Replies
23
Views
2K
Replies
3
Views
1K
Replies
9
Views
2K