MHB Find the equation of the tangent line (Can someone check my work?)

shamieh
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Find the equation of the tangent line to g(x) = arctan(x) + ln(x) @ x = 1

$$y - \frac{\pi}{4} = \frac{3}{2}(x - 1)$$
 
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Looks good to me. :D
 
shamieh said:
Find the equation of the tangent line to g(x) = arctan(x) + ln(x) @ x = 1

$$y - \frac{\pi}{4} = \frac{3}{2}(x - 1)$$

Your answer is indeed correct, but as no actual work is shown, we cannot verify that you didn't just happen to "guess" the right answer (although you probably didn't).

Things a teacher might want to see included in your answer:

1) What is g'(x)?

2) What is the formula for the tangent line to g(x) at x = a?

The correct two answers to the questions I have listed above are actually more important than "the final answer".
 
Deveno said:
Your answer is indeed correct, but as no actual work is shown...

This is an excellent point. If you answer happened to be incorrect, we would not have been able to address where you made any errors.
 
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