shamieh
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Find the equation of the tangent line to g(x) = arctan(x) + ln(x) @ x = 1
$$y - \frac{\pi}{4} = \frac{3}{2}(x - 1)$$
$$y - \frac{\pi}{4} = \frac{3}{2}(x - 1)$$
shamieh said:Find the equation of the tangent line to g(x) = arctan(x) + ln(x) @ x = 1
$$y - \frac{\pi}{4} = \frac{3}{2}(x - 1)$$
Deveno said:Your answer is indeed correct, but as no actual work is shown...