- #1

thomas49th

- 655

- 0

[tex]\frac{2\sqrt{3} - ln(2+\sqrt{3})}{4}[/tex]

Given that the x co-ordinate is [tex]ln(2+ \sqrt{3})[/tex] which I worked out in the first part of this qusetion given that at A there is a maximum turning point (so maximum turning point means dy/dx = 0), but I'm not sure that helps in this part of the question

y= -x + tanh4x

i tried [tex]y = -ln(2+ \sqrt{3}) + tanh4.ln(2+ \sqrt{3})[/tex] but can't really see how that simplifies :\

Thanks

Given that the x co-ordinate is [tex]ln(2+ \sqrt{3})[/tex] which I worked out in the first part of this qusetion given that at A there is a maximum turning point (so maximum turning point means dy/dx = 0), but I'm not sure that helps in this part of the question

y= -x + tanh4x

i tried [tex]y = -ln(2+ \sqrt{3}) + tanh4.ln(2+ \sqrt{3})[/tex] but can't really see how that simplifies :\

Thanks

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