Find the final velocity of the railroad car.

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SUMMARY

The problem involves a railroad car with a mass of 10,000 kg moving at an initial velocity of 4.00 m/s, which suddenly receives a 2,000 kg load of gravel. To find the final velocity of the railroad car after the gravel is added, the conservation of horizontal momentum must be applied. The initial momentum of the system (railroad car) is equal to the final momentum after the gravel is added, leading to the equation (m1 * v1) = (m1 + m2) * Vf, where m1 is the mass of the railroad car, v1 is its initial velocity, and Vf is the final velocity.

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  • Ability to manipulate algebraic equations
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ScullyX51
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Homework Statement


A 1.00×104 railroad car is rolling at 4.00 when a 2000 load of gravel is suddenly dropped in. What is the car's speed just after the gravel is loaded?


Homework Equations


f=ma
pi=pf


The Attempt at a Solution


I am very confused with this problem, but this is what I have tried so far:
I drew a "before" picture of mass1: 2000kg, and mass2: 1.00*10^4kg. both in the y direction.
Then I drew an "after" picture of "m1+m2" moving in the x direction (m1+m2)Vf. and vf is given to be 4 m/s.
I don't know what to do from here, and I am also very confused because it seems as though it is not conservation of momentum in the collision in the y direction because of the force of gravity, and the normal force from the train. I would appreciate if someone could give me some hints on how to approach this problem.
Thank you. :)
 
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ScullyX51 said:
I drew a "before" picture of mass1: 2000kg, and mass2: 1.00*10^4kg. both in the y direction.
What do you mean "in the y direction"?
Then I drew an "after" picture of "m1+m2" moving in the x direction (m1+m2)Vf.
This is good.
and vf is given to be 4 m/s.
No, 4 m/s is the initial velocity of the empty railroad car.

Hint: Just worry about the x-direction.
 
ScullyX51 said:

Homework Statement


A 1.00×104 railroad car is rolling at 4.00 when a 2000 load of gravel is suddenly dropped in. What is the car's speed just after the gravel is loaded?


Homework Equations


f=ma
pi=pf


The Attempt at a Solution


I am very confused with this problem, but this is what I have tried so far:
I drew a "before" picture of mass1: 2000kg, and mass2: 1.00*10^4kg. both in the y direction.
Then I drew an "after" picture of "m1+m2" moving in the x direction (m1+m2)Vf. and vf is given to be 4 m/s.
I don't know what to do from here, and I am also very confused because it seems as though it is not conservation of momentum in the collision in the y direction because of the force of gravity, and the normal force from the train. I would appreciate if someone could give me some hints on how to approach this problem.
Thank you. :)

Conservation of horizontal momentum is what you're after.
 

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