Find the flux (calculus problem)?

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SUMMARY

The discussion centers on calculating the flux of the vector field F = (x, 2y, z) across the surface S, defined as the portion of the cone (x² + z²)¹/² = y within the cylinder x² + z² = 1. The divergence theorem is employed, leading to the integral ∫∫s F · dS being transformed into a volume integral of the divergence of F, resulting in the expression 4 ∫∫∫ dV. The final calculation in cylindrical coordinates yields a flux value of 8π/3, though concerns are raised about the inclusion of the cone's base and the direction of the outward normal vector.

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Homework Statement



The directions for this calculus problem say find the flux of F across surface S (that is find the double integral F (ds)) where F = (x,2y,z), S is the part of the cone (x^2+z^2)^1/2=y inside of the cylinder x^2+z^2=1 and n points to the right.


Homework Equations



I'm pretty sure you need to use the divergence theorem here. So I guess ∫∫s F · dS is a relevant equation.

The Attempt at a Solution



Here is my work, along with the answer that I got. Please tell me if it is right.

∫∫s F · dS
= ∫∫∫ div F dV
= ∫∫∫ (1 + 2 + 1) dV
= 4 ∫∫∫ dV.

Now, convert this to cylindrical coordinates (with y playing the role of z):
4 ∫(θ = 0 to 2π) ∫(r = 0 to 1) ∫(y = 0 to r) r dy dr dθ
= 4 * 2π ∫(r = 0 to 1) r^2 dr
= 8π/3.
 
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The divergence theorem applies to flux outward from a closed volume. You haven't mentioned anything about the base(s) of the cone. Also, in that case the outward direction wouldn't be to the right.

Perhaps you are meant to calculate the flux directly. And how about the part of the cone where y < 0, is that included?

An exact statement of the problem is needed to know what you are actually trying to calculate.
 

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