Find the focus and directrix of the parabola

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Homework Help Overview

The discussion revolves around finding the focus and directrix of the parabola defined by the equation (y+2)² = 16(x-1). The subject area is conic sections, specifically parabolas.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to identify the focus and directrix using the standard form of a parabola. They express uncertainty about whether their calculations are complete. Other participants question the completeness of the original poster's response, particularly regarding the directrix.

Discussion Status

Contextual Notes

There is a mention of the original poster's calculations and the need for clarity on the directrix, suggesting that assumptions about the problem setup may need to be revisited.

louie3006
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Homework Statement



find the focus and directrix of the parabola:
(y+2)^2 = 16(x-1)

Homework Equations



(y-k)^2= 4a(x-h)
focus: ( h+a,k)
vertex: (h,k)

The Attempt at a Solution


k=-2,h=1,a=16/4=4!,
vertex at (1,-2)
focus ( 5,-2)
does that mean that i solved the problem or do i still to do more work to reach the final answer? thanks in advance.
 
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Well, did you find the focus and directrix?
 
i think i did , don't you think so ?
 
The directrix is a line. You don't have any line equations in your answer.
 
directrix : x=h-a
= 1-4
= -3 ? how about this, does look right to you, or am i wrong ?
 

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