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Find the friction force impeding its motion.

  1. Oct 16, 2006 #1
    Ok, our teacher is pretty much insane and doesn't teach anything at all. I'm sure this problem is incredibly simple, but I'm just not sure how to do it.

    Original Problem: A 15.0 kg box is released on a 32 degree incline and accelerates down the incline at .30m/s/s. Find the friction force impeding its motion. What is the coefficient of kinetic friction?

    What I Did: I found Normal Force to be 127 N with Wcos(theta) but I don't know where to go from there. Any help would be much appreciated.
  2. jcsd
  3. Oct 16, 2006 #2
    my teacher doesn't teach us anything either...except this ma=mgsin(theta)-umgcos(theta) then you can use that to solve for coefficient of kinetic friction and friction force. I think.
  4. Oct 16, 2006 #3
    thanks dude that works
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