Find the friction force impeding its motion.

Click For Summary
SUMMARY

The discussion focuses on calculating the friction force and the coefficient of kinetic friction for a 15.0 kg box on a 32-degree incline, which accelerates down the slope at 0.30 m/s². The normal force was calculated to be 127 N using the formula Wcos(theta). The correct approach to solve for the friction force involves applying the equation ma = mgsin(theta) - umgcos(theta), where u represents the coefficient of kinetic friction. This method effectively leads to the determination of both the friction force and the coefficient of kinetic friction.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Knowledge of trigonometric functions in physics
  • Familiarity with the concepts of normal force and gravitational force
  • Basic algebra for solving equations
NEXT STEPS
  • Study the derivation of the equation ma = mgsin(theta) - umgcos(theta)
  • Learn how to calculate the coefficient of kinetic friction using experimental data
  • Explore the effects of incline angles on friction and acceleration
  • Investigate real-world applications of friction in inclined planes
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of friction and motion on inclined planes.

nickrace09
Messages
2
Reaction score
0
Ok, our teacher is pretty much insane and doesn't teach anything at all. I'm sure this problem is incredibly simple, but I'm just not sure how to do it.

Original Problem: A 15.0 kg box is released on a 32 degree incline and accelerates down the incline at .30m/s/s. Find the friction force impeding its motion. What is the coefficient of kinetic friction?

What I Did: I found Normal Force to be 127 N with Wcos(theta) but I don't know where to go from there. Any help would be much appreciated.
 
Physics news on Phys.org
nickrace09 said:
Ok, our teacher is pretty much insane and doesn't teach anything at all. I'm sure this problem is incredibly simple, but I'm just not sure how to do it.

Original Problem: A 15.0 kg box is released on a 32 degree incline and accelerates down the incline at .30m/s/s. Find the friction force impeding its motion. What is the coefficient of kinetic friction?

What I Did: I found Normal Force to be 127 N with Wcos(theta) but I don't know where to go from there. Any help would be much appreciated.

my teacher doesn't teach us anything either...except this ma=mgsin(theta)-umgcos(theta) then you can use that to solve for coefficient of kinetic friction and friction force. I think.
 
thanks dude that works
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
Replies
24
Views
3K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
3K
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K