Find the greatest value of function

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SUMMARY

The discussion centers on finding the greatest value of the function defined by x( y-30)^2 under the constraint x + y = 60, where x and y are both greater than zero. The user initially calculated the maximum value at x = 10, yielding 4000, but later discovered that the function approaches a limit of 54000 as x approaches 60 from the left, indicating that the greatest value does not exist within the defined interval (0, 60). The function has a local maximum at x = 10 and a local minimum at x = 30, but it continues to increase as x approaches 60.

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Homework Statement


If x + y = 60 and x,y >0 find greatest value of x( y-30)^2


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The Attempt at a Solution


I did this by the usual method that is by substituting 60 - x for y and then differentiating the function and equating derivative to zero.
I got x = 10 and x=30. At x=30 value is zero and at x=10 value is 4000 so my answer was 4000
But i checked the solution it says that greatest value does not exist
It gave the hint that limit x-->60(-) f(x) = 54000 so greatest value does not exist

I'm lost here because the function ought to have some greatest value. Help!
 
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hi jd12345! :smile:
jd12345 said:
At x=30 value is zero and at x=10 value is 4000 so my answer was 4000
But i checked the solution it says that greatest value does not exist
It gave the hint that limit x-->60(-) f(x) = 54000 so greatest value does not exist

sketch the graph …

it has a local maximum at 10, a local minimum at 30, at keeps increasing above 30

it is only defined on (0,60) (not [0,60]), so it never reaches the value it would have at 60 ! :wink:
 
Ok it maeks sense now - thank you
 

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