Find the Lagrangian of this single mass system

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The discussion centers on verifying the setup and equations for the Lagrangian of a single mass system involving springs with zero equilibrium lengths. Participants clarify that zero equilibrium length means the spring has no length when unstressed, leading to specific interpretations of elastic potential energy. The equations for potential energy are debated, with emphasis on using the current length of the spring in calculations. Questions arise about the choice of origin for the coordinate system and the conservation of momentum, with explanations linking these to the dynamics of the system. Overall, the conversation focuses on ensuring the accuracy of the Lagrangian formulation and understanding the implications of the spring characteristics.
MyoPhilosopher
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Homework Statement
Find the lagrangian of the following system (pic included below)
Relevant Equations
L = T - U
1582971855522.png


1582971879118.png
 
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Is there a question in this ?
 
BvU said:
Is there a question in this ?
sorry, is my Langragian set up and equations correct?
 
Did you check them thoroughly ? That should be enough, shouldn't it ?
 
BvU said:
Did you check them thoroughly ? That should be enough, shouldn't it ?
Thanks for the help
 
MyoPhilosopher said:
sorry, is my Langragian set up and equations correct?
What does it mean that the springs have zero equilibrium lengths?
What is the elastic potential energy?
 
ehild said:
What does it mean that the springs have zero equilibrium lengths?
What is the elastic potential energy?
1. I understand it as that at the mass in the center of the blocks and at y=0 in my pic, and lengths L/2 for each spring, is 0 equilibrium
2. I have the two elastic PEs in the post above individually
 
MyoPhilosopher said:
1. I understand it as that at the mass in the center of the blocks and at y=0 in my pic, and lengths L/2 for each spring, is 0 equilibrium
2. I have the two elastic PEs in the post above individually
Zero equilibrium length means zero length when the spring is unstretched. You assumed that the unstretched length is L.
What is the formula for the potential energy of a spring?
 
Zero equilibrium length means spring energy is zero at spring length zero. Unrealistic, but pobably set like that to make it easier for you !
 
  • #10
ehild said:
Zero equilibrium length means zero length when the spring is unstretched. You assumed that the unstretched length is L.
What is the formula for the potential energy of a spring?
I assumed the unstreched length of each spring was L/2. 1/2 * k(Δx)^2
 
  • #11
BvU said:
Zero equilibrium length means spring energy is zero at spring length zero. Unrealistic, but pobably set like that to make it easier for you !
Alright so my equations for potential should quite literally use the (ΔLength = current length). so essentially 0.5k(0-currentl length)^2
 
  • #12
That is my interpretation, yes.
 
  • #13
Quesion: why did you choose the origin like that, instead of at the very center ?
 
  • #14
BvU said:
That is my interpretation, yes.
That makes sense thank you I misread and misunderstood that. Can I ask why the momentum of the mass or object is not conserved? Would be due to constantly changing velocities of the object?
 
  • #15
BvU said:
Quesion: why did you choose the origin like that, instead of at the very center ?
My first attempt was using polar coordinates but that did not work easily. I chose those points to get a clear x_dot and y_dot for my kinetic energy.
 

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