Find the Laurent Series for f(z)=1/(z(z-1)) Valid on 1<|z-1|<infinity

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SUMMARY

The discussion focuses on finding the Laurent series for the function f(z) = 1/(z(z-1)), valid in the annular region defined by 1 < |z-1| < ∞. The approach involves rewriting the function to isolate the term 1/(z-1) and then applying the geometric series expansion for 1/(1 + 1/(z-1)). The series expansion leads to terms of the form (z-1)^-n, which can be multiplied by the other factors to derive the complete Laurent series.

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Homework Statement


Find the Laurent series for f(z)=1/(z(z-1)) valid on 1<|z-1|<infinity


Homework Equations


1/(1+a)=1-a+a^2-a^3... where |a|<1
we are not supposed to use integrals for this problem

The Attempt at a Solution


I want 1/(z-1) to be in my final answer, so I have 1/(z(z-1))=(1/(z-1))(1/(z-1))(1/(1+1/(z-1))=(*)
I can then expand the last of the three terms in (*) as 1/(1-1/(z-1))=1-(z-1)^-1+(z-1)^-2 etc.
Is this right? can I then multiply it by the first two (multiplicative) terms in (*) to get an extra (z-1)^-2 in each term of the series
 
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