What is Laurent series: Definition and 162 Discussions

In mathematics, the Laurent series of a complex function f(z) is a representation of that function as a power series which includes terms of negative degree. It may be used to express complex functions in cases where a Taylor series expansion cannot be applied. The Laurent series was named after and first published by Pierre Alphonse Laurent in 1843. Karl Weierstrass may have discovered it first in a paper written in 1841, but it was not published until after his death.The Laurent series for a complex function f(z) about a point c is given by




f
(
z
)
=



n
=








a

n


(
z

c

)

n


,


{\displaystyle f(z)=\sum _{n=-\infty }^{\infty }a_{n}(z-c)^{n},}
where an and c are constants, with an defined by a line integral that generalizes Cauchy's integral formula:





a

n


=


1

2
π
i






γ





f
(
z
)


(
z

c

)

n
+
1






d
z
.


{\displaystyle a_{n}={\frac {1}{2\pi i}}\oint _{\gamma }{\frac {f(z)}{(z-c)^{n+1}}}\,dz.}
The path of integration



γ


{\displaystyle \gamma }
is counterclockwise around a Jordan curve enclosing c and lying in an annulus A in which



f
(
z
)


{\displaystyle f(z)}
is holomorphic (analytic). The expansion for



f
(
z
)


{\displaystyle f(z)}
will then be valid anywhere inside the annulus. The annulus is shown in red in the figure on the right, along with an example of a suitable path of integration labeled



γ


{\displaystyle \gamma }
. If we take



γ


{\displaystyle \gamma }
to be a circle




|

z

c

|

=
ϱ


{\displaystyle |z-c|=\varrho }
, where



r
<
ϱ
<
R


{\displaystyle r<\varrho <R}
, this just amounts
to computing the complex Fourier coefficients of the restriction of



f


{\displaystyle f}
to



γ


{\displaystyle \gamma }
. The fact that these
integrals are unchanged by a deformation of the contour



γ


{\displaystyle \gamma }
is an immediate consequence of Green's theorem.
One may also obtain the Laurent series for a complex function f(z) at



z
=



{\displaystyle z=\infty }
. However, this is the same as when



R




{\displaystyle R\rightarrow \infty }
(see the example below).
In practice, the above integral formula may not offer the most practical method for computing the coefficients





a

n




{\displaystyle a_{n}}
for a given function



f
(
z
)


{\displaystyle f(z)}
; instead, one often pieces together the Laurent series by combining known Taylor expansions. Because the Laurent expansion of a function is unique whenever
it exists, any expression of this form that actually equals the given function




f
(
z
)


{\displaystyle f(z)}
in some annulus must actually be the Laurent expansion of



f
(
z
)


{\displaystyle f(z)}
.

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  1. T

    A Laurent series for algebraic functions

    Hi, I'm writting because I sort of had an idea that looks that it should work but, I did not find any paper talking about it. I was thinking about approximating something like algebraic functions. That is to say, a function of a complex variable z,(probably multivalued) that obeys something...
  2. L

    Multiplication of Taylor and Laurent series

    First series \frac{1}{2}\sum^{\infty}_{n=0}\frac{(-1)^n}{n+1}(\frac{1}{p^2})^{n+1}= \frac{1}{2}(\frac{1}{p^2}-\frac{1}{2p^4}+\frac{1}{3p^6}-\frac{1}{4p^8}+...) whereas second one is...
  3. docnet

    Find the Laurent Series of a function

    (a) i tried to decompose the fracion as a sum of fractions of form ##\frac{1}{1-g}## $$f=\frac{-z}{(1+z)(2-z)}=\frac{a}{1+z}+\frac{b}{2-z}$$ $$a=\frac{1}{3}, b=-\frac{2}{3}$$ $$f=\frac{1}{6}\frac{1}{1+z}-\frac{1}{3}\frac{1}{1-\frac{z}{2}}$$ $$f=\frac{1}{6}\sum_{n=0}^\infty...
  4. HansBu

    Laurent Series (Complex Analysis)

    My homework is on mathematical physics and I want to know the concept behind Laurent series. I want to know clearly know the process behind attaining the series representation for the expansion in sigma notation using the formula that can be found on the attached files. There are three questions...
  5. C

    MHB Using Cauchy Integral Formula for Laurent Series Coefficients

    Dear Everyone, I am wondering how to use the integral formula for a holomorphic function at all points except a point that does not exist in function's analyticity. For instance, Let $f$ be defined as $$f(z)=\frac{z}{e^z-i}$$. $f$ is holomorphic everywhere except for $z_n=i\pi/2+2ni\pi$ for...
  6. C

    Manipulating a Laurent Series Equation

    Not really a homework problem, just an equation from my textbook that I do not understand. I can't think of any way to even begin manipulating the right hand side to make it equal the left hand side. Just to confirm equality (thanks to another user for suggestion), I multiplied both sides by of...
  7. T

    Finding residues with Laurent series.

    Homework Statement Use an appropriate Laurent series to find the indicated residue for ##f(z)=\frac{4z-6}{z(2-z)}## ; ##\operatorname{Res}(f(z),0)## Homework Equations n/a The Attempt at a Solution Computations are done such that ##0 \lt \vert z\vert \lt 2##...
  8. binbagsss

    Quick question on Laurent series proof uniqueness

    Homework Statement I am looking at the wikipedia proof of uniqueness of laurent series: https://en.wikipedia.org/wiki/Laurent_seriesHomework Equations look above or belowThe Attempt at a Solution I just don't know what the indentity used before the bottom line is, I've never seen it before...
  9. A

    Laurent series of z^2sin(1/(z-1))

    Homework Statement Find Laurent series of $$z^2sin(\frac{1}{1-z})$$ at $$0<\lvert z-1 \rvert<\infty$$ Homework Equations sine series expansion. The Attempt at a Solution At first, it seems pretty elementary since you can set w=\frac{1}{z-1} and expand at infinity in z, which is 0 in w...
  10. binbagsss

    Laurent series expansion of ℘(z).

    Homework Statement Homework EquationsThe Attempt at a Solution [/B] Hi, I am trying to understand the 2nd equality . I thought perhaps it is an expansion of ##(1-\frac{z}{w})^{-2}## (and then the ##1## cancels with the ##1## in ##( (1-\frac{z}{w})^{-2}) -1 ) ##) in the form ##(1-x)^{-2}##...
  11. C

    Expanding f(z) in a Laurent Series for |z|>3

    Homework Statement expand f(z)=\frac{1}{z(z-1)} in a laurent series valid for the given annular domain. |z|> 3 Homework EquationsThe Attempt at a Solution first I do partial fractions to get \frac{-1}{3z} +\frac{1}{3(z-3)} then in the second fraction I factor out a z in the denominator...
  12. binbagsss

    Laurent series by long division of trig function

    Homework Statement Hi I am trying to understand this http://math.stackexchange.com/questions/341406/how-do-i-obtain-the-laurent-series-for-fz-frac-1-cosz4-1-about-0 So the long division yields...
  13. K

    Complex Analysis. Laurent Series Expansion in region(22C).

    <Moderator's note: moved from a technical forum, so homework template missing> Hi. I have solved the others but I am really struggling on 22c. I need it to converge for |z|>2. This is the part I am really struggling with. I am trying to get both fractions into a geometric series with...
  14. binbagsss

    Complex analysis f'/f , f meromorphic, Laurent series

    Homework Statement consider ##f## a meromorphic function with a finite pole at ##z=a## of order ##m##. Thus ##f(z)## has a laurent expansion: ##f(z)=\sum\limits_{n=-m}^{\infty} a_{n} (z-a)^{n} ## I want to show that ##f'(z)'/f(z)= \frac{m}{z-a} + holomorphic function ## And so where a...
  15. MAGNIBORO

    I What is the role of Laurent series in solving limits at infinity?

    hi, I try to calculate the integral $$\int_{0}^{1}log(\Gamma (x))dx$$ and the last step To solve the problem is: $$1 -\frac{\gamma }{2} + \lim_{n\rightarrow \infty } \frac{H_{n}}{2} + n + log(\Gamma (n+1)) - (n+1)(log(n+1))$$ and wolfram alpha tells me something about series expansion at...
  16. M

    A Laurent series at infinity

    Question 1: Find the Laurent series of \cos{\frac{1}{z}} at the singularity z = 0. The answer is often given as, \cos\frac{1}{z} = 1 - \frac{1}{2z^2} + \frac{1}{24z^4} - ... Which is the MacLaurin series for \cos{u} with u = \frac{1}{z}. The MacLaurin series is the Taylor series when u_0 = 0...
  17. Pouyan

    Expanding f(z) in a Laurent Series

    Homework Statement Expand the function f(z)=1/z(z-2) in a Laurent series valid for the annual region 0<|z-3|<1 Homework Equations I know 1/z(z+1) = 0.5(1/(z-2)) - 0.5(1/z) Taylor for 0.5(1/(z-2)) is : ∑(((-1)k/2) * (z-3)k) (k is from 0 to ∞)For the second 0.5(1/z) the answer is a...
  18. P

    Singularities and Laurent series

    Homework Statement Classify the singularities of ##\frac{1}{z^{1/4}(1+z)}## Find the Laurent series for ##\frac{1}{z^2-1}## around z=1 and z=-1 Homework EquationsThe Attempt at a Solution So for the first bit there exists a singularity at ##z=0##, but I'm confused about the order of this...
  19. P

    Classifying Singularities and the Laurent Series

    Homework Statement Classify the singularities of ##\frac{1}{z^2sinh(z)}## and describe the behaviour as z goes to infinity Find the Laurent series of the above and find the region of convergence Homework Equations N/A The Attempt at a Solution I thought these two were essentially the same...
  20. P

    Laurent series of e^(1/z)

    Homework Statement Cassify the singularities of e^\frac{1}{z} and find the Laurent series Homework Equations e^\frac{1}{x} =\sum \frac{(\frac{1}{x})^n}{n!} The Attempt at a Solution Theres a singularity at z=0, but I need to find the order of the pole So using the general expression for the...
  21. saybrook1

    Trouble with an index change in Laurent series

    Homework Statement Hey guys, I'm just going through a Laurent series example and I'm having trouble understanding how they switched the index on a summation from n=0 to n=1 and then switched the argument from z^(-n-1) to z^n as well as changing the upper limit to -infinity. If anyone could shed...
  22. Crush1986

    How can I find the Laurent series for Cos(1/z) at z=0?

    Homework Statement I need to find the Laurent Series of Cos[\frac{1}{z}] at z=0 Homework Equations None The Attempt at a Solution I've gone through a lot of these problems and this is one of the last on the problem set. With all the other trig functions it's been just computing their...
  23. I

    Laurent series of rational function in annulus

    Homework Statement Find the Laurent expansions of ##f(z) = \frac{z+2}{z^2-z-2}## in ##1 < |z|<2## and then in ##2 < |z|< \infty## in powers of ##z## and ##1/z##. Homework Equations Theorem: Let ##f## be a rational function all of whose poles ##z_1,\dots , z_N## in the plane have order one and...
  24. I

    Finding Laurent Series and Residues for Complex Functions

    Homework Statement Find four terns of the Laurent series for the given function about ##z_0=0##. Also, give the residue of the function at the point. a) ##\frac{1}{e^z-1}## b) ##\frac{1}{1-\cos z}## Homework Equations The residue of the function at ##z_0## is coefficient before the...
  25. sinkersub

    A: Reciprocal series, B: Laurent Series and Cauchy's Formula

    Problem A now solved! Problem B: I am working with two equations: The first gives me the coefficients for the Laurent Series expansion of a complex function, which is: f(z) = \sum_{n=-\infty}^\infty a_n(z-z_0)^n This first equation for the coefficients is: a_n = \frac{1}{2πi} \oint...
  26. sinkersub

    Inverse Binomial Expansion within Laurent Series?

    Homework Statement Find the Laurent Series of f(z) = \frac{1}{z(z-2)^3} about the singularities z=0 and z=2 (separately). Verify z=0 is a pole of order 1, and z=2 is a pole of order 3. Find residue of f(z) at each pole. Homework Equations The solution starts by parentheses in the form (1 -...
  27. ognik

    MHB What region for Laurent series

    Please help me with this Laurent series example for $\frac{1}{z(z+2)}$ in the region 1 < |z-1| < 3 Let w = z-1, then $ f(z) = \frac{1}{(w+1)(w+3)}=\frac{1}{2} \left[ \frac{1}{w+1}-\frac{1}{w+3} \right]$ I get $ \frac{1}{1-(-w)} = \sum_{n=0}^{\infty}(-1)^n w^n, \:for\: |w|<1;$ $ = -...
  28. J

    How can I find the first few terms of the Laurent series for

    Homework Statement For each of the following functions find the first few terms of each of the Laurent series about the origin, that is, one series for each annular ring between singular points. Find the residue of each function at the origin. The function is... 1/(z*(z-1)(z-2)^2) Homework...
  29. ognik

    MHB Understanding the Laurent Series of $\frac{1}{z(z-1)(z-2)}$

    Blundering on, this problem will help me confirm what I think I know ... Find the Laurent series for $ f(z) = \frac{1}{z(z-1)(z-2)} = \frac{1}{2z}+\frac{1}{1-z} -\frac{1}{4}\frac{1}{1-\frac{z}{2}} $ I found this definition of the LS: $ f(z) = \sum_{-\infty}^{+\infty}{a}_{n}(z-{z}_{0})^n =...
  30. ognik

    MHB Find coefficiant of Laurent series, without using residue

    Hi - I admit to struggling a little with my 1st exposure to complex analysis and Laurent series in particular, so thought I'd try some exercises; always seem to help my understanding. A function f(z) expanded in Laurent series exhibits a pole of order m at z=z0. Show that the coefficient of $...
  31. ognik

    MHB On the use of Laurent series

    My book is a little confusing sometimes, and googling doesn't always help. Just a couple of queries - and please add any of your own 'tips & tricks'... 1) Laurent series (LS) is defined from $ -\infty $, yet all the examples I have seen start from 0 - I can't think of an annulus with a...
  32. M

    Use Residue Theorems or Laurent Series to evaluate integral

    Homework Statement Evaluate the integral using any method: ∫C (z10) / (z - (1/2))(z10 + 2), where C : |z| = 1 Homework Equations ∫C f(z) dz = 2πi*(Σki=1 Resp_i f(z) The Attempt at a Solution Rewrote the function as (1/(z-(1/2)))*(1/(1+(2/z^10))). Not sure if Laurent series expansion is the...
  33. S

    MHB Laurent series, integral of a holomorphic function

    We are given f = \sum_{n= - \infty} ^{\infty} a_n (z-z_0)^n \in \mathcal{O} (ann (z_0, r, R)), \ \ 0<r<R< \infty . Prove that \frac{1}{\pi} \int _{ann (z_0, r, R)} |f(z)|^2 d \lambda(z) = \sum _{n \neq -1} \frac{R^{2n+2} - r^{2n+2}}{n+1}|a_n|^2 + 2 \log \frac{R}{r}|a_{-1}|^2. We know that the...
  34. B

    Laurent series expansion of Log(1+1/(z-1))

    Homework Statement Find the Laurent series expansion of f(z) = \log\left(1+\frac{1}{z-1}\right) in powers of \left(z-1\right). Homework Equations The function has a singularity at z = 1, and the nearest other singularity is at z = 0 (where the Log function diverges). So in theory there should...
  35. KleZMeR

    Expanding Laurent Series around Singularities

    Homework Statement Determine Laurent Series around z = -1, z = 2, z=0 Determine pole and residue in each case, and solve series in each separate region of C. f_1(z) = \frac {z}{(z+1)(z-2)} Homework EquationsThe Attempt at a Solution I've determined my partial fractions as \frac{1}{3}...
  36. A

    MHB Check answer for laurent series

    Hello. Can you check if my answer is correct please? For the region ${\{z\inℂ\big|0<|z|<1\}}$, expand $\frac{1}{z^3-z^4}$ that has a center z=0 into Laurent series. My solution: $$\frac{1}{z^3(1-z)}=\frac{1}{z^3}\sum_{n=0}^{\infty}z^n=\sum_{n=0}^{\infty}z^{n-3}$$
  37. M

    Laurent Series Part 2: Expanding 1/(z^2+1) at z=-i

    Hello. I am stuck on this question. Let {##z\in ℂ|0<|z+i|<2##}, expand ##\frac{1}{z^2+1}## where its center ##z=-i## into Laurent series. This is how I start off: $$\frac{1}{(z+i)(z-i)}$$ And then I don't know what to do next. I guess geometric series could be applied later but I...
  38. A

    MHB How to Expand a Complex Function into a Laurent Series?

    Hello. I am stuck on this question. Let {$z\in ℂ|0<|z+i|<2$}, expand $\frac{1}{z^2+1}$ where its center $z=-i$ into Laurent series. I have no idea how to start. I guess geometric series could be applied later but I don't know how to start.
  39. M

    Laurent Series: Exploring the Expansion of e^(z^2)/z^3 at z=0

    Hello. I need explanation about this Laurent series. The question is: Let {##z\inℂ|0<|z|##}, expand ##\frac{e^{z^2}}{z^3}## where the centre z=0 into Laurent series. And the solution is...
  40. A

    MHB How do I expand $\frac{e^{z^2}}{z^3}$ into a Laurent series?

    Hello. I need explanation about this Laurent series. The question is: Let {$z\inℂ|0<|z|$}, expand $\frac{e^{z^2}}{z^3}$ where the centre z=0 into Laurent series. And the solution is...
  41. S

    MHB Expand e^{\frac{z}{z-2}} Laurent Series: z=2

    expand e^{\frac{z}{z-2}} in a Laurent series about z=2 I cannot start this. my attempt so far has been e^\frac{z}{z-2}=1 + \frac{z}{z-2} + \frac{z^2}{(z-2)^2 2!} + \frac{z^3}{(z-2)^3 3!} This is unlike the other problems I have worked. Seems I need to manipulate this equation some way...
  42. S

    MHB Calculating Residues Using Laurent Series

    Hi guys, well i have the problem below, $$\int_{\gamma(0;1)}\frac{1}{\exp(iz)-1}\mathrm{d}z$$ so it is holormorphic in D'(0,1) as it has a point not holomorphic at z=0. Taking a Laurent Series in the form $$f(z)=\sum_{n=-\infty}^{\infty}C_n(z-0)^n$$ But i wil get...
  43. C

    Harmonic function on annulus and finding Laurent series

    Homework Statement a)Find a harmonic function ##u## on the annulus ##1< |z| < 2## taking the value 2 in the circle ##|z|=2## and the value 1 in the circle ##|z|=1##. b)Determine all the isolated singularities of the function ##f(z) = \frac{z+1}{z^3+4z^2+5z+2}## and determine the residue at...
  44. T

    Partial Fractions in Laurent Series Expansion

    Homework Statement f = \frac{1}{z(z-1)(z-2)} Homework Equations Partial fraction The Attempt at a Solution R1 = 0 < z < 1 R2 = 1 < z < 2 R3 = z > 2 f = \frac{1}{z(z-1)(z-2)} = \frac{1}{z} * (\frac{A}{z-1} + \frac{B}{z-2}) Where A = -1 , B = 1. f = \frac{1}{z} *...
  45. R

    Need help finding a Laurent Series

    Homework Statement Let f(z) = \frac{1}{z^2-1}. Find Laurent Series valid for the following regions. • 0<|z−1|<2 • 2<|z−1|<∞ • 0<|z|<1 Homework Equations \frac{1}{1-z}=\sum^{\infty}_{n=0}z^n,\: |z|<1 f(z)=\sum^{\infty}_{n=0}a_n(z-z_0)^n+\sum^{\infty}_{n=1}b_n(z-z_0)^{-n} The Attempt at a...
  46. binbagsss

    Laurent Series & Partial Fraction Decomposition.

    Okay so the partial fraction decomposition theorem is that if f(z) is a rational function, f(z)=sum of the principal parts of a laurent expansion of f(z) about each root. I'm working through an example in my book, I am fine to follow it. (method 1 below) But instinctively , I would have...
  47. S

    Expand function in Laurent series

    Homework Statement Expand ##f(z)=\frac{1}{z^2(z-1)}## in Laurent series for ##0<|z-1|<1##. Use binomial series. Homework Equations The Attempt at a Solution I am looking at this problem for quite some time now and still I got nothing. I do however think that this will come in...
  48. S

    Singularity points + Laurent series

    Homework Statement Find and determine the type of singularity points for ##f(z)=\frac{\sin(3z)-3z}{z^5}##. Also calculate the regular and main part of Laurent series around those points.Homework Equations The Attempt at a Solution I am already having troubles with the first part. Singularity...
  49. G

    Question about understanding something in laurent series

    So the question I got the represention for both partial fractions after I broke the functions into two partial fraction one I got as 1/3(z + 1) + 2/3(z - 2) and I got laurent series represention for both but I was wondering for |z| < 1 how can they both converge for |z| < 1 are we acctually...
  50. N

    Finding the Laurent Series of e^(1/(1-z)) for Residue Calculation

    Homework Statement Hi! I need to find the laurent series of ##e^{1/(1-z)}## to get the residue at ##z=1##. Can somebody help me? The Attempt at a Solution https://scontent-a-ams.xx.fbcdn.net/hphotos-frc3/q71/s720x720/1461607_10201796752217165_1002449331_n.jpg I tried using the taylor series...
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