1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Find the line of intersection between 2 Planes

  1. Oct 30, 2006 #1
    Hello,

    I am trying to find the line of intersection between these two planes:

    [tex]P_1[/tex] = x + 2y -9z = 7
    [tex]P_2[/tex] = 2x - 3y + 17z = 0

    I found the direction vector needed for the line of intersection between these two points by taking the cross product of the [tex]P_1[/tex] normal vector and the [tex]P_2[/tex] normal vector which gave me [tex]\vec{a}[/tex] = <7,-35,-7>

    Now all I need is a point somewhere along the direction of that vector. This is where I am stuck. Any help on finding this point would be awesome. Thanks!!

    ~Peter
     
  2. jcsd
  3. Oct 30, 2006 #2

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    Why find the equations of the line that way? Since you have two equations for three unknown variables, just solve for two of them in terms of the third, then use that third variable as parameter.

    For example, to find equations of the line of intersection of x+ y+ z= 1 and 2x- y+ z= 0, adding the equations gives 3x+ 2z= 1 so z= 1/2- (3/2)x.
    Then y= 1- x- z= 1- x- 1/2+ (3/2)z= 1/2+ (1/2)x. Let x= t. Then the parametric equations are x= t, y= 1/2+ (1/2)t, z= 1/2- (3/2)t. In vector form, [tex]\vec{r}= t\vec{i}+ (1/2+ (1/2)t)\vec{j}+ (1/2- (3/2)t)\vec{k}[/tex] or [tex]\vec{r}= ((1/2)\vec{j}+ (1/2)\vec{k})+ (\vec{i}+ (1/2)\vec{j}+ (1/2)\vec{k})t[/tex].
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Find the line of intersection between 2 Planes
Loading...