Find the Linear Speed of a Bucket in a Well with Hand Crank at 1.15 m/s

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The discussion centers on calculating the linear speed of a bucket being lowered into a well via a hand crank with a tangential speed of 1.15 m/s. The crank has a diameter of 0.400 m, while the stick to which the bucket is attached has a diameter of 0.100 m. To find the linear speed of the bucket, one must apply the relationship between the tangential speed of the crank and the radius of the crank and the stick. This problem exemplifies the principles of rotational motion and linear speed conversion.

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Here is my problem...

A person lowers a bucket into a well by turning the hand crank, as the figure illustrates. The crank handle moves with a constant tangential speed of 1.15 m/s on its circular path. Find the linear speed with which the bucket moves down the well. The diameter of the turning hand crank is .400m and the diameter of the stick that the bucket is tied to is .100m.
 
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Kris1120 said:
Here is my problem...

A person lowers a bucket into a well by turning the hand crank, as the figure illustrates. The crank handle moves with a constant tangential speed of 1.15 m/s on its circular path. Find the linear speed with which the bucket moves down the well. The diameter of the turning hand crank is .400m and the diameter of the stick that the bucket is tied to is .100m.
Hi Kris and welcome to PF,

We are more than happy to help you will any homework questions you may have. However, you are required to show some effort in solving the question yourself.

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