Find the loss for the power inversion that would take place in the UPS

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SUMMARY

The discussion centers on calculating the power loss due to inversion in the Sola SDU500 UPS during power outages. The UPS has a capacity of 500 VA and 300 Watts, with a load power factor of 0.6. The estimated power consumption for the system is approximately 12 Wh, with a total load of 205 Wh/day. The UPS provides a backup time of 4 minutes at full load, translating to 20 watt-hours, factoring in inverter efficiency. Caution is advised against connecting laser printers to this UPS due to potential performance degradation from power spikes.

PREREQUISITES
  • Understanding of UPS specifications, including capacity and power factor.
  • Knowledge of power consumption calculations in watt-hours.
  • Familiarity with inverter efficiency and its impact on backup time.
  • Awareness of load types and their effects on UPS performance.
NEXT STEPS
  • Research "Sola SDU500 UPS specifications" for detailed performance metrics.
  • Learn about "power factor correction" and its importance in UPS systems.
  • Investigate "inverter efficiency" and its role in power loss calculations.
  • Explore "UPS load management" to optimize performance and longevity.
USEFUL FOR

Electrical engineers, IT professionals, and anyone involved in power management and UPS system optimization will benefit from this discussion.

harmander
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Hey guys,

I tried to figure this out and got a rough estimate but thought I’d ask the experts.

I use the Sola SDU500 UPSs in our systems. A customer wants to know how long they will last if there is a power outage. I believe the power consumption for the entire system would be ~12Wh
total load will be 205 Wh/day

The specs for the UPS are as follows:

· Capacity (VA/Watts): 500/300
· Load power factor: .6
· Back-up time: 4.5/18 (full load/half load)

I can’t seem to find the loss for the power inversion that would take place in the UPS.

Let me know what you think
 
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Here is the data sheet

http://datasheet.octopart.com/SDU500-Sola-datasheet-22869.pdf

It says 4 mins (not 4.5) at 300 watts which equals 4/60 * 300 = 20 watt-hours at full belt.

This takes into account the conversion efficiency in the inverter.

Don't know what your system is but do not connect a printer, particularly a laser, to this UPS as you will get spikes that will greatly degrade performance.
 

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