An 8.50 kg point mass and a 13.5 kg point mass are held in place 50.0 cm apart. A particle of mass m is released from a point between the two masses 19.0 cm from the 8.50 kg mass along the line connecting the two fixed masses.(adsbygoogle = window.adsbygoogle || []).push({});

Find the magnitude of the acceleration of the particle.

Fg=(Gm1m2)/r^2

G=6.67*10^-11

m1=8.50kg

m2=13.5

r=(50/2)/100=.25m

so Fg =((6.67*10^-11)*8.50*13.5)/(.25^2)

Fg=1.2246*10^-7

F=ma since particle close to 8.5kg

a= 1.2246*10^-7/8.50

=1.440*10^-8 m/s^2

why this answer wrong please help me

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# Homework Help: Find the magnitude of the acceleration of the particle.

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