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saturn67
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An 8.50 kg point mass and a 13.5 kg point mass are held in place 50.0 cm apart. A particle of mass m is released from a point between the two masses 19.0 cm from the 8.50 kg mass along the line connecting the two fixed masses.
Find the magnitude of the acceleration of the particle.
Fg=(Gm1m2)/r^2
G=6.67*10^-11
m1=8.50kg
m2=13.5
r=(50/2)/100=.25m
so Fg =((6.67*10^-11)*8.50*13.5)/(.25^2)
Fg=1.2246*10^-7
F=ma since particle close to 8.5kg
a= 1.2246*10^-7/8.50
=1.440*10^-8 m/s^2
why this answer wrong please help me
Find the magnitude of the acceleration of the particle.
Fg=(Gm1m2)/r^2
G=6.67*10^-11
m1=8.50kg
m2=13.5
r=(50/2)/100=.25m
so Fg =((6.67*10^-11)*8.50*13.5)/(.25^2)
Fg=1.2246*10^-7
F=ma since particle close to 8.5kg
a= 1.2246*10^-7/8.50
=1.440*10^-8 m/s^2
why this answer wrong please help me