Group of particles in a magnetic field

In summary, the proton experiences a force of 2.25 x 10-16 N in the +y direction and an electron experiences a force of 8.50 x 10-16 N in the +y direction when traveling in a magnetic field of unknown magnitude and direction.
  • #1
fishturtle1
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Homework Statement


A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.50 km/s in the +x-direction experiences a force of 2.25 x ##10^{-16}##N in the +y-direction, and an electron moving at 4.75 km/s in the -z-direction experiences a force of 8.50 x ##10^{-16}##N in the +y-direction. a) What are the magnitude and direction of the magnetic field?

Homework Equations


Right hand rule
F = |q|vB
##\vec F = qv##x##\vec B##

The Attempt at a Solution


info for proton:
##m_1 = 1.6727 * 10^{-27} kg##
##q_1 = +1.602 * 10^{-19} C##
##\vec v_1 = 1500 m/s## in the +x direction.
##\vec F_1 = 2.25 * 10^{-16} N## in the +y direction.

info for the electron:
##m_2 = 9.110 * 10^{-31} kg##
##q_2 = -1.602*10^{-19} C##
##\vec v_2 = 4750 m/s## in the -z direction
##\vec F_2 = 8.50 * 10^{-16} ## in the +y direction

,i'm pretty sure I solved for B correctly incase you want to skip this part..
##\vec B = <b_1, b_2, b_3>##then i do cross product to solve for the B components.

first equation, for proton:
##<0, 2.25 * 10^{-16}, 0> = q<1500, 0, 0>##x##<b_1, b_2, b_3>##
second equation, for electron:
##<0,8.50*10^{-16}, 0> = -q<0, 0, -4750>##x##<b_1, b_2, b_3>##
where ##q = +1.602*10^{-19}##

first equation simplifies to this:
##q<1500, 0, 0>##x##<b_1, b_2, b_3>##
##= q<0, -1500b_3, 1500b_2>##
## = <0, -1500b_3q, 1500b_2q##

second equation simplifies to this:
##-q<0, 0, -4750>##x##<b_1, b_2, b_3>##
##= -q<4750b_2, -4750b_1, 0>##
##= <-4750b_2q, 4750b_1q, 0>##

so now i have 2 equations:
##<0, 2.25 * 10^{-16}, 0> = <0, -1500b_3q, 1500b_2q##
##<0,8.50*10^{-16}, 0> = <-4750b_2q, 4750b_1q, 0>##

##b_3 = \frac {2.25*10^{-16}} {-1500q} = -.936##
##b_2 = 0##
##b_1 = \frac {8.50*10^{-16}} { 4750q} = 1.117##

##B = \sqrt {(-.936)^2 + (1.117)^2} = 1.46T##

now when i try to do the right hand rule.. i get confused
what i know is velocity direction is the thumb, force direction is the palm, and magnetic field direction are the fingers.

but there are 2 velocities and 2 forces... so i try to do it for both of them..

for the proton my thumb points toward me, my palm faces to my right, and so my fingers point toward the floor. So the magnetic field is South.

for the electron my thumb points toward the floor, my palm faces to my right, and so my fingers point away from me. So the magnetic field is in the -x direction.

How can I find the direction?
 
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  • #2
First off, the two sets of forces and velocities must not contradict each other, this is a good way to ensure your answer is correct. You are to check each of them separately. What you said about the right hand rule is correct, and so is your calculation so let's go over the two particles:

(Important to note that the cross product is additive, so each of the two cross products can be broken down into a sum or cross products between the unit vectors. As you've calculated the B field has a positive x component and a negative z component, this already tells you the direction: somewhere between the x and z axises in that xz plane, the angle itl be from the x-axis will be arctan(b3/b1).)To check this field actually exerts the forces given we can use the right hand rule:

proton: Velocity is in the x direction and so is your thumb. now we look at the 2 components of the B-field:
b1: the x component is parallel to the velocity and therefore has no effect, cross product between two parellel vectors always gives 0.
b3: thumb with the x-axis and fingers at negative z gives positive y direction for your palm, as given in the question

electron: velocity is in the negative z direction and so is your thumb. examine both components of the vector:
b1: thumb to negative x and fingers (b1=B component in the x direction that you found) to the x direction leaves your palm facing the negative y direction. recall the electron charge is negative so we flip the direction (multiply by -1). we get the positive y direction again for the force, as given in the question.
b3: this component is parallel to the velocity and therefore has no effect.

make sure you're using a right handed cartesian coordinate system and that you are in fact using the right hand ! (i made that mistake in an exam once..)

Another way to see it: the cross product of two vectors ⃗v = ⟨v1, v2, v3⟩ and w⃗ = ⟨w1, w2, w3⟩ in space is

defined as the vector:
⃗v×w⃗ =⟨v2w3 −v3w2,v3w1 −v1w3,v1w2 −v2w1⟩.
 
  • #3
Ok.. I followed your right hand rule steps to find the direction, thank you
 

1. What is a group of particles in a magnetic field?

A group of particles in a magnetic field refers to a collection of particles, such as atoms or subatomic particles, that are placed within the influence of a magnetic field. This means that the particles will experience a force due to the presence of the magnetic field.

2. How does a magnetic field affect a group of particles?

A magnetic field can affect a group of particles in several ways. One way is by exerting a force on the particles, causing them to move in a particular direction. Another way is by aligning the particles in a specific orientation, depending on the strength and direction of the magnetic field.

3. What is the difference between a magnetic field and an electric field?

A magnetic field is a region in which a magnetic force can be detected, while an electric field is a region in which an electric force can be detected. The main difference between the two is that magnetic fields are produced by moving charges, while electric fields are produced by stationary charges.

4. How are particles affected by a magnetic field?

Particles can be affected by a magnetic field in different ways, depending on their properties and the strength of the field. Generally, particles with electric charge will experience a force in a direction perpendicular to both their velocity and the magnetic field. Additionally, the velocity of the particles may be altered as they move through the field.

5. What is the significance of studying groups of particles in a magnetic field?

Studying groups of particles in a magnetic field is crucial for understanding many natural phenomena, such as the behavior of atoms and molecules, the production of electricity, and the structure and function of materials. It also has practical applications in fields such as engineering, medicine, and technology.

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