Max Speed of Piston in Simple Harmonic Motion

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Homework Help Overview

The discussion revolves around the maximum speed of a piston in simple harmonic motion, specifically in the context of an automobile engine. The original poster presents a problem involving a 1 kg piston that travels a total distance of 10 cm at an engine speed of 3000 rpm, seeking assistance in determining the maximum speed of the piston.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conversion of engine speed from rpm to rad/sec and its relevance to the problem. There are inquiries about the formula needed to find maximum velocity and the relationship between amplitude and the total distance traveled by the piston. Some participants express uncertainty about how to derive necessary quantities such as amplitude and spring constant.

Discussion Status

The discussion is active, with participants exploring various formulas related to kinetic and potential energy. Some guidance has been offered regarding the relationship between maximum velocity and amplitude, as well as the angular velocity. There is an ongoing exchange of ideas about how to express total energy in terms of known quantities.

Contextual Notes

Participants note the challenge of missing values needed for calculations, such as the spring constant and specific velocity. The problem's constraints include the requirement to derive relationships without plugging in all values at once.

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The motion of a piston in an automobile engine is nearly simple harmonic. If the 1 kg piston travels back and forth over a total distance of 10 cm, what is the maximum speed (magnitude of velocity) when the engine is running at 3000 rpm? (Hint: the 10 cm distance has something to do with amplitude; 3000 rpm needs to be converted to rad/sec)


I did convert the 3000 rpm, and I got 314.159 rad/sec.


I need some help with this problem a.s.a.p. I don't know where to go with it. Thanks for any help you can give me.
 
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What formula do you think you will need here?
 
I don't know, and I don't know any way to find A. I keep thinking that A has something to do with the 3000 rpm, but I am not sure.
 
What formula(s) do you know that would allow you to find the maximum velocity?
 
Dark Visitor said:
I don't know, and I don't know any way to find A. I keep thinking that A has something to do with the 3000 rpm, but I am not sure.

A is the amplitude. If the piston moves, from minimum to maximum, a distance of 10cm, what distance does it move when it goes from 0 to maximum?
 
5 cm? Cause 10 cm would be the total length, while +A is half, and -A is the other half.
 
Dark Visitor said:
5 cm? Cause 10 cm would be the total length, while +A is half, and -A is the other half.

Right good. Now can you formulate an equation for speed given kinetic energy is 1/2mv2 and potential energy is 1/2kx2. What is the formula for the total energy?
 
E = K + U

(K is kinetic energy, u is potential energy)

But using the equations you gave, I am missing most of the quantities. How can I use them?
 
Dark Visitor said:
E = K + U

(K is kinetic energy, u is potential energy)

But using the equations you gave, I am missing most of the quantities. How can I use them?

I told you K and U, if you get an expression for E, you will get what you need with the quantities you know.
 
  • #10
But for K, I need a velocity, which I don't have.

And for U, I need a spring constant value for k, but we have x (10 cm).
 
  • #11
Dark Visitor said:
But for K, I need a velocity, which I don't have.

And for U, I need a spring constant value for k, but we have x (10 cm).

you don't need to plug in all the values at one time. Just formulate and then see if you can get the terms needed.

what is E in terms of k and A?
 
  • #12
Well since I don't have all the values I need, I get:

K = 1/2(1 kg)(v)2

and

U = 1/2(k)(.01 m)2

and then we still have E = K + U
 
  • #13
Dark Visitor said:
Well since I don't have all the values I need, I get:

K = 1/2(1 kg)(v)2

and

U = 1/2(k)(.01 m)2

and then we still have E = K + U

do not put in the values as yet.

E=\frac{1}{2}mv^2+\frac{1}{2}kx^2

Do you know another way to re-write E in terms of k and A?
 
  • #14
I think what is being asked for is an equation that resembles the other oscillators.


x(t)=A Sin(argument in t) where your argument has you hitting both extremes at a rate of 50 times a second, say by multiplying t by something like 100 * pi (314.15)
Now remember to get the max velocity, you need to know when acceleration is zero.
The velocity is -wA sin(wt). sin(wt) is at most 1.0. Hope this helps, I've been at this most of the day and am burnt to a crisp.
 
  • #15
So do I use the equation:

vmax = wA ? Or what? I am really confused on this one...
 
  • #16
Dark Visitor said:
So do I use the equation:

vmax = wA ? Or what? I am really confused on this one...
YES! Vmax=wA. Good job. Sorry if I'm a little fried and testy.
 
  • #17
Dark Visitor said:
So do I use the equation:

vmax = wA ? Or what? I am really confused on this one...


yes, had you derived it, you would get v_{max}=\omega A
 
  • #18
No, don't be. I owe you big time for all of your help today, and I would be the same way if I was helping someone like me.

Now that I got that right, where do I get my w and A values?
 
  • #19
Dark Visitor said:
No, don't be. I owe you big time for all of your help today, and I would be the same way if I was helping someone like me.

Now that I got that right, where do I get my w and A values?

A is the amplitude that you found, and w is the angular velocity you converted in the first post.
 
  • #20
Okay, and I got:

vmax = (314.159 rad/s)(.05 m)
= 15.71 m/s


Thanks a lot, both of you, for your help. I appreciate it more than you know. :redface:
 

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