Find the Net Force on Ball A from Balls B & C

Click For Summary

Homework Help Overview

The problem involves calculating the net gravitational force acting on Ball A due to Balls B and C, each weighing 3.00 kg and positioned at specified distances from Ball A. The context is rooted in gravitational force calculations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the vector nature of forces and the need to consider the direction of each force acting on Ball A. There are attempts to calculate the forces exerted by Balls B and C and questions about how to combine these forces to find the net force.

Discussion Status

The discussion includes various calculations of gravitational forces and considerations of their directions. Some participants express uncertainty about the setup and the net force calculation, while others clarify the positions of the balls relative to Ball A.

Contextual Notes

There is ambiguity in the initial problem description regarding the positions of the balls, which has led to some confusion in the discussion. Participants are working with the assumption that gravitational forces decrease with distance.

bigtymer8700
Messages
40
Reaction score
0

Homework Statement


Each ball weighs 3.00 kg A is 10cm from C to the left and B is 40cm to the right of A


Homework Equations



F=Gm1m2/r^2

The Attempt at a Solution



ive tried adding the forces that each ball apply to A and subtracting it. i know each has its own force acting on A but don't know how to figure it out with 3 objects
 
Physics news on Phys.org
Force is a vector. You have two force acting in opposite directions on ball A. How would you work out the net force then?
 
Well you already know that each force is acting in the x direction and with gravity the farther away the less the gravitational force so wouldn't you just have to subtract the sum of each force?
 
F=6.67e-11 (3kg) (3kg))/.04^2 i calculated that for the force of B on A and i got 3.75e-7N

for force of C on A i got 6.003e-7N. Now each of these balls is exerting its own force on A but one is stronger than the other because of the distance so isn't the net force just calculated by the difference?
 
If you have to calculate the net force on A then both balls B and C are to the right of it and the forces will add. I was a bit unsure which ball you were wanting to calculate the net force on. The description of the system was a bit ambiguous as well.
 
In the picture given to me Ball C is to the left of A and ball B is to the right they are on different sides sorry if the description was hazy.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
Replies
30
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
43
Views
5K
Replies
7
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 13 ·
Replies
13
Views
9K
Replies
8
Views
2K