Find the object location with ray optics

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SUMMARY

The discussion centers on determining the image location and orientation for a 1.0-cm-tall object placed 4.0 cm from a diverging lens with a focal length of 6.0 cm. Using the thin lens formula, the image distance (si) is calculated to be -2.40 cm, indicating a virtual image. The user also attempted ray tracing but encountered discrepancies in measurement, specifically measuring 0.4 cm instead of the calculated value. The solution emphasizes the importance of accurately drawing rays, particularly the horizontal ray that refracts through the focal point.

PREREQUISITES
  • Understanding of thin lens formula: -1/f = 1/so + 1/si
  • Knowledge of ray optics and ray tracing techniques
  • Familiarity with the concept of virtual images in optics
  • Basic skills in measurement and diagram drawing
NEXT STEPS
  • Study the principles of ray optics and their applications in lens systems
  • Practice ray tracing with various lens types, focusing on diverging lenses
  • Explore the implications of virtual images in optical systems
  • Learn about the significance of focal points in lens behavior
USEFUL FOR

Students studying optics, physics educators, and anyone seeking to understand the behavior of light through lenses, particularly in the context of diverging lenses and image formation.

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Homework Statement



A 1.0-cm-tall object is placed 4.0cm from a diverging lens of focal length 6.0cm. Using both ray tracing and the thin lens formula, find the location and orientation of the image.

Homework Equations


-1/f = 1/so + 1/si
m = -si/so = hi/ho


The Attempt at a Solution


-1/6cm = 1/4cm + 1/si
si = -2.40 cm

Okay so attached my ray tracing diagram.. (sorry for the crappy camera quality), but the point where the Si crosses the ho is supposed to be where the object distance is.. and i measured with my ruler that it is 0.4cm, not 2.4cm. What am I doing wrong in the drawing?
 

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    2012-11-26 21.37.35.jpg
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You haven't correctly drawn the ray that travels horizontally toward the lens. Hint: for this ray you'll need to use one of the focal points.
 
Rays traveling parallel to the principal axis are refracted through the focal point of the lens.
 

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