Find the percentage of electrons were removed?

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SUMMARY

The discussion centers on calculating the percentage of electrons removed from a neutral object containing 7.2e26 electrons after 9.5e6 electrons are extracted. The correct calculation involves dividing the number of removed electrons by the total number of electrons and then multiplying by 100 to convert the result into a percentage. The accurate percentage of electrons removed is 1.32e-18, which is derived from the formula (9.5e6 / 7.2e26) * 100. The confusion arose from not applying the percentage conversion step.

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Homework Statement


A neutral object contains an equal number of positive and negative charges. A particular neutral object contains 7.2e26 electrons. If 9.5e6 electrons are removed, what percentage of the electrons where removed?


Homework Equations


coulomb = 6.24e18 electrons

elentary charge = 1.6 E -19 coulombs


The Attempt at a Solution


I'm having difficulties of solving the percentage of the electrons were removed,

I did this:

9.5e6 / 7.2e26 = 1.32e-20

But the answer says it's 1.32e-18, so I don't know how it got that answer.

Any help will be appreciated.

Thanks
 
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blackbyron said:

Homework Statement


A neutral object contains an equal number of positive and negative charges. A particular neutral object contains 7.2e26 electrons. If 9.5e6 electrons are removed, what percentage of the electrons where removed?


Homework Equations


coulomb = 6.24e18 electrons

elentary charge = 1.6 E -19 coulombs


The Attempt at a Solution


I'm having difficulties of solving the percentage of the electrons were removed,

I did this:

9.5e6 / 7.2e26 = 1.32e-20

But the answer says it's 1.32e-18, so I don't know how it got that answer.

Any help will be appreciated.

Thanks

To convert a number to a percentage, multiply by 100.
 
Mark44 said:
To convert a number to a percentage, multiply by 100.

Wow, I forgot about that. What am I thinking? haha thanks.
 

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