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SUMMARY

The discussion centers on the calculation of velocity during a two-minute acceleration period in a physics problem. The correct formula applied is V = U + at, where U is the initial velocity of 20 m/s, a is the acceleration of 0.2 m/s², and t is the time of 120 seconds. The accurate final velocity after the acceleration is determined to be 44 m/s, not 64 m/s, due to the miscalculation of the initial velocity. This error impacts subsequent calculations for stopping time, distance, and the overall graph representation.

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Homework Statement
I've completed it but I don't think it's right could someone please check?
Relevant Equations
Equations of motion
See question and attempt answer below. Thanks.
 

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i), ii) and iii) I agree with your answers.

However check your calculation for the velocity after the initial 2 min acceleration...

V=U+at
U=20 m/s
a=0.2 m/s/s
t=120 s (2min)

= 20 + (0.2*120)
= 20 + 24
= 44m/s

eg not 64m/s

I think you double counted the initial 20m/s.

That effects the stopping time and distance and the time at constant velocity.
 
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As explained above, answer iv) and graph are not correct because the calculated value of speed for end of acceleration period/beginning of slope is too high.
For same reason, calculated times values are not correct.
 

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