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Elm956
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Homework Statement
Hint: Disregard any dissipative effects of the
atmosphere of the planet.
A projectile is launched from the surface of a planet (mass M, radius R)
with a launch speed equal to 61 percent of the escape speed for that
planet. The projectile will rise to a maximum height and fall back to the
surface of the planet. What will be the ratio of its maximum height above
the surface to radius of the planet, h/R?
Homework Equations
1/2mv² = -Gmm/R
Vf² = Vi² - 2gh
The Attempt at a Solution
1. 1/2mv² = -Gmm/R
v² = -2Gm/R
v = .61√(2Gm/R)
2. Vf² = Vi² - 2gh
0 = Vi² - 2gh
Vi² = 2gh
Vi = √2gh
3. .61√(2Gm/R) = √(2Gh)
.7442(Gm/R) = 2(Gmh/R²)
.7442Gm = 2(Gmh/R)
.7442 = 2h/R
h/R = .3721
Any thoughts or advice on the incorrect answer? Thanks in advance.