1. The problem statement, all variables and given/known data Hint: Disregard any dissipative effects of the atmosphere of the planet. A projectile is launched from the surface of a planet (mass M, radius R) with a launch speed equal to 61 percent of the escape speed for that planet. The projectile will rise to a maximum height and fall back to the surface of the planet. What will be the ratio of its maximum height above the surface to radius of the planet, h/R? 2. Relevant equations 1/2mv² = -Gmm/R Vf² = Vi² - 2gh 3. The attempt at a solution 1. 1/2mv² = -Gmm/R v² = -2Gm/R v = .61√(2Gm/R) 2. Vf² = Vi² - 2gh 0 = Vi² - 2gh Vi² = 2gh Vi = √2gh 3. .61√(2Gm/R) = √(2Gh) .7442(Gm/R) = 2(Gmh/R²) .7442Gm = 2(Gmh/R) .7442 = 2h/R h/R = .3721 Any thoughts or advice on the incorrect answer? Thanks in advance.