Find the real roots of an equation.

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Discussion Overview

The discussion revolves around finding the real roots of the equation $\displaystyle x^3+2ax+\frac{1}{16}=-a+\sqrt{a^2+x-\frac{1}{16}}$ for $0

Discussion Character

  • Homework-related
  • Exploratory
  • Technical explanation

Main Points Raised

  • One participant expresses uncertainty about how to begin solving the problem and seeks assistance.
  • Another participant suggests starting by squaring both sides of the equation to form a sixth-order polynomial, indicating a potential method to approach the solution.
  • A participant asks for the source of the problem and whether a closed form solution is necessary.
  • Further clarification is provided regarding the source of the problem, referencing the USSR Olympiad Problem Book.
  • One participant mentions a suspected typo in the problem statement, suggesting that the first term should be $x^2$ instead of $x^3$, and shares a link to a PDF that may contain the correct version.
  • A later post indicates an attempt to apply the correction but concludes that the method does not work, expressing frustration with the algebra involved.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct formulation of the problem or the methods to solve it. There are competing views regarding the equation's terms and the effectiveness of proposed solutions.

Contextual Notes

There are unresolved issues regarding the accuracy of the problem statement, particularly concerning the potential typo. The discussion also reflects varying levels of familiarity with the problem-solving techniques required.

anemone
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Hello to all members of the forum,

Problem:
Find the real roots of the equation
$\displaystyle x^3+2ax+\frac{1}{16}=-a+\sqrt{a^2+x-\frac{1}{16}}\;\;\; (0<a<\frac{1}{4}) $

I really have no idea on how to even start to work with this problem, could anyone please help me?

Thanks.
 
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anemone said:
Hello to all members of the forum,

Problem:
Find the real roots of the equation
$\displaystyle x^3+2ax+\frac{1}{16}=-a+\sqrt{a^2+x-\frac{1}{16}}\;\;\; (0<a<\frac{1}{4}) $

I really have no idea on how to even start to work with this problem, could anyone please help me?

Thanks.


You should probably start with

$\displaystyle \begin{align*} x^3 + 2ax + \frac{1}{16} &= -a + \sqrt{a^2 + x - \frac{1}{16} } \\ x^3 + 2ax + \frac{1}{16} + a &= \sqrt{a^2 + x - \frac{1}{16}} \\ \left( x^3 + 2ax + \frac{1}{16} + a \right)^2 &= a^2 + x - \frac{1}{16} \end{align*}$

Now expand everything, and try to solve the resulting 6th order polynomial equation if possible...
 
anemone said:
Problem:
Find the real roots of the equation
$\displaystyle x^3+2ax+\frac{1}{16}=-a+\sqrt{a^2+x-\frac{1}{16}}\;\;\; (0<a<\frac{1}{4}) $


Hello anemone,

Could you provide the source and/or context? Is it necessary a closed form solution?
 
anemone said:

A little story: yesterday I spend two hours tryng to solve the problem without success, so I had a suspection. Browsing on the net I saw the solution in a pdf. There is a typo, in the left side the first term is $x^2$ instead of $x^3$. Have a look at the following link

http://www.fernandorevilla.es/wp-content/uploads/2013/02/olympiad.pdf

There are at least two ways of solving the problem. The first way (I tried in the same way with $x^3$) using a graphical method, the second one using an horrible method. Ask your doubts.
 
anemone said:
Hello to all members of the forum,

Problem:
Find the real roots of the equation
$\displaystyle x^2+2ax+\frac{1}{16}=-a+\sqrt{a^2+x-\frac{1}{16}}\;\;\; (0<a<\frac{1}{4}) $

I really have no idea on how to even start to work with this problem, could anyone please help me?

Thanks.

Using Fernando Revilla's correction to the problem, and hoping my algebra is working properly today:

... forget it, it does not work ..
 
Last edited:
zzephod said:
... forget it it does not work ..

At any rate, thanks for your contribution and welcome to MHB.
 

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