Finding value in a complex set region

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    Complex Set Value
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Homework Help Overview

The problem involves determining the largest value of r for which a specific region defined by complex numbers is contained within another region. The context is rooted in complex analysis and geometric interpretation of sets in the complex plane.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the geometric representation of the sets involved, including the circle and line equations. There is uncertainty about how to proceed with finding the maximum value of r, with suggestions of using differentiation or graphical methods.

Discussion Status

The discussion is active, with participants exploring different interpretations of the problem and suggesting various approaches. Some guidance has been offered regarding the geometric aspects of the problem, but no consensus has been reached on the method to solve it.

Contextual Notes

Participants are working with constraints defined by the equations of a circle and a line, and there is some confusion regarding the specific forms of these equations. The options for the value of r are also being debated.

Raghav Gupta
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Homework Statement



The largest value of r for which the region represented by the set { ω ε C / |ω - 4 - i| ≤ r}
is contained in the region represented by the set { z ε C / |z - 1| ≤ |z + i|}, is equal to :
√17
2√2
3/2 √2
5/2 √2

Homework Equations


complex number = a + ib where a,b ε R

The Attempt at a Solution


Don't know how to start or what to apply
 
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Hi!
Hint: the set |w-4-i| ≤r represents the region inside the circle with its centre (4, 1) and radius r.
 
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Hello Mooncrater
Okay, we know centre of circle as (4,1) and radius r.
Now taking z= x + iy,
we get from question
(x - 1)2 + y2 ≤ x2+ (y+1)2
⇒ -x ≤ y
Now what?
 
Now each equation(the circle and the line) points out where a point can be.. like a constraint.
 
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So should we differentiate to get max. Value of r?
Is it a minima and maxima problem?
 
You can do it through graph... it will be very easier then. I think maxima would work if you want it to do it that way...
 
Is the D option 5√2/2 or 5/2√2?
 
mooncrater said:
Now each equation(the circle and the line) points out where a point can be.. like a constraint.
What's the line equation?
Is it y = -x ?
And circle equation is (x-4)2 + (y-1)2 = r2 ?
mooncrater said:
Is the D option 5√2/2 or 5/2√2?
The D option is 5√2/2 .
 
Raghav Gupta said:
What's the line equation?
Is it y = -x ?
And circle equation is (x-4)2 + (y-1)2 = r2 ? .
Yes.
 
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Got it, thanks the D option.
 
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