- #1

transgalactic

- 1,395

- 0

find the solution of this ln equation:

ax=lnx

i tried:

[tex]

e^{(ax)}=x

[/tex]

[tex]

e^{(ax)}-x=0

[/tex]

what to do next??

i thought of building a taylor series around 0 for ln

but ln(0) is undefined

??

ax=lnx

i tried:

[tex]

e^{(ax)}=x

[/tex]

[tex]

e^{(ax)}-x=0

[/tex]

what to do next??

i thought of building a taylor series around 0 for ln

but ln(0) is undefined

??

Last edited: