Find the Speed and Direction of a Wave with Constants A, B, and C

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Homework Help Overview

The problem involves determining the speed and direction of a wave described by the equation y(x,t)=Ae^{Bx^2+BC^2t^2-2BCxt}, where A, B, and C are constants. The discussion centers around the characteristics of the wave and the implications of the mathematical form of the equation.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the transformation of the wave equation and question the necessity of an imaginary constant in the exponential term. There are discussions about the implications of having a diverging or decaying exponential versus a plane wave.

Discussion Status

The discussion is active, with participants presenting differing views on the inclusion of an imaginary constant and its relevance to the wave equation. Some participants assert their interpretations while others challenge these assumptions, leading to a dynamic exchange of ideas.

Contextual Notes

There is mention of the wave equation and its requirements, indicating that the original poster's equation may not satisfy these conditions without certain modifications. The discussion reflects a lack of consensus on the correct form of the wave equation.

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Homework Statement


What's the speed and direction of the following wave(A,B and C are constants)
y(x,t)=Ae^{Bx^2+BC^2t^2-2BCxt}


The Attempt at a Solution


y(x,t)=Ae^{B(x-Ct)^2}

from (x-Ct)

v=C in the +x direction
 
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Are you missing the imaginary constant in your exponential? If so, then you are correct. If not, you have a diverging or decaying exponential rather than a plane wave.
 
No,it's original question.There's no imaginary constant.
So my solution is true.Thanks for checking.
 
No, there has to be an imaginary constant. You need to have something of the form

Ae^{i(x-vt)}

Regular exponentials don't satisfy the wave equation. The wave equation says that two derivatives in time equal two derivatives in space divided by the velocity squared.
 

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