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Find the speed with which the box hits the ground.

  1. Oct 19, 2012 #1
    1. The problem statement, all variables and given/known data
    A box whose mass is 4kg is at rest on the floor. It is then lifted to a height of 2m by a constant a constant force F and then released. At this point the box has upward velocity of 5m/s. Do not use Newton's laws of motion to solve this problem.

    A. Find magnitude of the force F
    F=65N

    B. Find the speed with which the box hits the ground.
    ???
    2. Relevant equations
    g = 10m/s^2


    3. The attempt at a solution

    A. Wother = ΔKE + ΔPE = 65N magnitude of force

    B. 0 = 1/2mvf^2-1/2m(0)^2 + mg(0) - mghi
    = 1/2mvf^2 - mghi
    vf = √[(2*mghi)/m] = √2*4*10*2/4 = 6.32 m/s (WRONG)

    The speed is supposed to be = 8.09 m/s
    I just killed the constant force in the work and substituted in the values as if the box fell to ground. I don't know what i'm missing.

    I will return soon.
     
  2. jcsd
  3. Oct 19, 2012 #2

    TSny

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    Why zero here?
     
    Last edited: Oct 19, 2012
  4. Oct 19, 2012 #3
    I assumed it had to be zero for either final or initial velocity. so i can solve for v. i first tried vf = 0m/s to say the object has landed, and then i'd solve for vi with this formula.
     
  5. Oct 20, 2012 #4

    When you solve for v...
    0=½mv^2-mgh_i
    ½mv^2=mgh_i |:m |*2
    v^2=2gh_i
    v=√(2gh_i)
     
  6. Oct 20, 2012 #5
    Why does one velocity have to be zero? You were given an initial velocity (vi=+5m/s), and you are told to find a final velocity (vf). By your logic, vf must be zero. This makes no sense for two reasons:
    1. The ball is accelerating downwards, so as long as it starts from any height above the ground, it should have nonzero velocity when it hits the ground.
    2. If you are told to find something, it is very rarely zero.
     
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