Taylor series for 28^(3/5) around x=2

[peripatein]

Hello,

What polynomial should I use for finding Taylor series for 28^(3/5) up to the first order? I mean, aside x^3 around 2. Any suggestions?

 

[ehild]

Use the Taylor series of f(x)=x^(3/5) around a=32 (=2^5).

ehild

 

[peripatein]

Did you not mean to write =2^3 (Instead of "=2^5")?

 

[peripatein]

I know that 32=2^5.

 

[HallsofIvy]

Yes, and that is the fifth power of an integer that is closest to 28. That's the point.