MHB Find the total number of marbles that Ahmad and Weiming have in terms of x.

  • Thread starter Thread starter Johnx1
  • Start date Start date
  • Tags Tags
    Terms
AI Thread Summary
Ahmad has x marbles, which is 40 more than Weiming, meaning Weiming has x - 40 marbles. The total number of marbles they have is expressed as T = 2x - 40. When Ahmad has 55 marbles, the total becomes T = 2(55 - 20) = 70. The confusion arose from misinterpreting the relationship between Ahmad's and Weiming's marbles.
Johnx1
Messages
48
Reaction score
0
Ahmad has x marbles. He has 40 more marbles than Weiming

a) Find the total number of marbles that Ahmad and Weiming have in terms of x.

my answer: x + x + 40. So 2x + 40

b) Ahmad has 55 marbles. How many marbles do they have altogether?

my answer: 2(55)+ 40 = 150
 
Mathematics news on Phys.org
Johnx said:
Ahmad has x marbles. He has 40 more marbles than Weiming

a) Find the total number of marbles that Ahmad and Weiming have in terms of x.

my answer: x + x + 40. So 2x + 40

b) Ahmad has 55 marbles. How many marbles do they have altogether?

my answer: 2(55)+ 40 = 150

That looks good! (Yes)
 
Thanks for the reply.

The reason why I asked this question is because there is a different answer.

a) answer: 2x - 40

b) answer: 2 * 55 - 40 - 70I'm not sure why this other answer said to subtract 40.
 
Johnx said:
Thanks for the reply.

The reason why I asked this question is because there is a different answer.

a) answer: 2x - 40

b) answer: 2 * 55 - 40 - 70I'm not sure why this other answer said to subtract 40.

Because we both made the same mistake reading the problem. We are told:

Ahmad has x marbles. He has 40 more marbles than Weiming

This means Weiming has 40 less marbles than Ahmad, which means Weiming has \(x-40\) marbles, and so the total \(T\) is:

$$T=x+x-40=2x-40=2(x-20)$$

And so if Ahmad has 55 marbles, we find:

$$T=2(55-20)=2\cdot35=70$$

Sorry for the confusion! :)
 
No worries and thank you.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Thread 'Imaginary Pythagoras'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...

Similar threads

Replies
8
Views
2K
Replies
8
Views
2K
Replies
4
Views
3K
Replies
3
Views
898
Replies
7
Views
2K
Replies
3
Views
1K
Back
Top