Find the total number of marbles that Ahmad and Weiming have in terms of x.

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Discussion Overview

The discussion revolves around determining the total number of marbles that Ahmad and Weiming have, expressed in terms of a variable x. The problem includes both a theoretical aspect of forming an equation based on given conditions and a specific numerical example.

Discussion Character

  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • Some participants propose that the total number of marbles is given by the expression 2x + 40, based on the understanding that Ahmad has x marbles and 40 more than Weiming.
  • Others argue that the total should be expressed as 2x - 40, suggesting that Weiming has x - 40 marbles, leading to a different total.
  • A later reply questions the reasoning behind the subtraction of 40 in the alternative answer, indicating confusion about the interpretation of the problem.
  • One participant clarifies that since Ahmad has x marbles and is 40 more than Weiming, Weiming must have x - 40 marbles, resulting in a total of 2x - 40.
  • In the numerical example, some participants calculate the total when Ahmad has 55 marbles, arriving at different totals based on their interpretations of the initial conditions.

Areas of Agreement / Disagreement

Participants express differing views on how to interpret the problem, leading to multiple competing answers. The discussion remains unresolved regarding which interpretation is correct.

Contextual Notes

There is uncertainty regarding the assumptions made about the relationship between Ahmad's and Weiming's marbles, particularly in how the additional 40 marbles are factored into the total. The mathematical steps leading to the different answers are not fully resolved.

Johnx1
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Ahmad has x marbles. He has 40 more marbles than Weiming

a) Find the total number of marbles that Ahmad and Weiming have in terms of x.

my answer: x + x + 40. So 2x + 40

b) Ahmad has 55 marbles. How many marbles do they have altogether?

my answer: 2(55)+ 40 = 150
 
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Johnx said:
Ahmad has x marbles. He has 40 more marbles than Weiming

a) Find the total number of marbles that Ahmad and Weiming have in terms of x.

my answer: x + x + 40. So 2x + 40

b) Ahmad has 55 marbles. How many marbles do they have altogether?

my answer: 2(55)+ 40 = 150

That looks good! (Yes)
 
Thanks for the reply.

The reason why I asked this question is because there is a different answer.

a) answer: 2x - 40

b) answer: 2 * 55 - 40 - 70I'm not sure why this other answer said to subtract 40.
 
Johnx said:
Thanks for the reply.

The reason why I asked this question is because there is a different answer.

a) answer: 2x - 40

b) answer: 2 * 55 - 40 - 70I'm not sure why this other answer said to subtract 40.

Because we both made the same mistake reading the problem. We are told:

Ahmad has x marbles. He has 40 more marbles than Weiming

This means Weiming has 40 less marbles than Ahmad, which means Weiming has \(x-40\) marbles, and so the total \(T\) is:

$$T=x+x-40=2x-40=2(x-20)$$

And so if Ahmad has 55 marbles, we find:

$$T=2(55-20)=2\cdot35=70$$

Sorry for the confusion! :)
 
No worries and thank you.
 

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