Find the True Statement About Dot Product of Two Vectors

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SUMMARY

The discussion centers on determining the true statement regarding the dot product of two vectors resulting in -1. The correct answer is option C, which states that the vectors must be between 90 and 270 degrees from each other. This conclusion is derived from the equation A·B = |A||B|cosθ, where the cosine of the angle must be negative to yield a negative dot product. Options A, B, D, and E are eliminated based on the properties of the cosine function and the definitions of vector magnitudes.

PREREQUISITES
  • Understanding of vector operations, specifically dot products.
  • Familiarity with trigonometric functions and their properties.
  • Knowledge of angles in degrees and their implications in vector mathematics.
  • Basic algebraic manipulation of equations involving vectors.
NEXT STEPS
  • Study the geometric interpretation of the dot product in vector analysis.
  • Learn about the implications of vector angles on dot product values.
  • Explore the relationship between vector magnitudes and their directional properties.
  • Investigate applications of dot products in physics and engineering contexts.
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Students studying linear algebra, physics enthusiasts, and anyone interested in understanding vector mathematics and its applications in real-world scenarios.

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Homework Statement



The dot product of.two vectors is -1which of the following statements is true

A. They must be unit vectors pointing in opposite directions.
B. They must be unit vectors pointing j. The same direction.
C. They must be more than 90( and less than 270 )degrees from each other.
D. They must be perpendicular to each other.
E. They must sum to zero

Homework Equations


I have eliminated D though I find the others difficult

The Attempt at a Solution

 
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A.B = |A||B|cosθ .So we are looking at the product of three quantities whose product is -1 .Two quantities are magnitudes ,hence positive.Now only cosθ term can be negative .

Now rethink about the options .A few of them can be eliminated .
 
\vec{u}\circ\vec{v}=|\vec{u}|\cdot|\vec{v}|\cos\angle(\vec{u},\vec{v})=-1\Rightarrow<br /> \cos\angle(\vec{u},\vec{v})&lt;0\Rightarrow 90^o&lt;\angle(\vec{u},\vec{v})&lt;270^o
the same direction: \cos\angle(\vec{u},\vec{v})=\cos 0^o=1\Rightarrow \vec{u}\circ\vec{v}\ge 0&gt;-1 so not B

2i\circ\left(-\frac{1}{2}i\right)=-1
so not A nor E
 
Tanya Sharma said:
A.B = |A||B|cosθ .So we are looking at the product of three quantities whose product is -1 .Two quantities are magnitudes ,hence positive.Now only cosθ term can be negative .

Now rethink about the options .A few of them can be eliminated .


Ok so in order to obtain a negative value the value of the angle would have to be between 90 and 270 then this leaves option ' c' is that so?
 
Correct ...
 

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