Find the type of equilibrium at (0,0) for x'=x, y'=y

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SUMMARY

The equilibrium point at (0,0) for the system of differential equations x' = x and y' = y is determined to be an unstable node. The analysis shows that as both x and y approach zero, their derivatives remain positive, indicating that the system diverges from the equilibrium point. The solution involves integrating the equations to find the relationship between x and y, leading to the conclusion that the equilibrium is unstable without the use of matrices.

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Homework Statement



I need to solve the differential equations given, find the type and stability of the equilibrium at (0,0), without matricies.

Homework Equations



none

The Attempt at a Solution



starting:

x' = x
y' = y

dy/dx = y'/x' = y/x

=> dy/y = dx/x

integrating gives

ln y + c1 = lnx + c2

rearrange and get

ln(y/x) = c


have i done it right so far?
i get stuck at this point
 
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I'm only wondering why you are solving for y as a function of x at all.

dx/dt= x, dy/dt= y. What is true about the derivatives if x and y both close to 0 but positive?
 

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