Find the velocity of an object to become a satellite of Eart

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SUMMARY

The discussion focuses on calculating the velocity required for an object at a height of 500 km above Earth's surface to become a satellite. The equation used is a = v²/r, where the user calculated a velocity of 8306 m/s, while the correct velocity is 7600 m/s. The discrepancy arises from an incorrect value for acceleration (a) and the radius (r) used in the calculations. Clarification on the definitions of these variables is necessary for accurate computation.

PREREQUISITES
  • Understanding of gravitational acceleration and its value near Earth's surface.
  • Familiarity with the concept of orbital mechanics.
  • Knowledge of the formula a = v²/r and its application in physics.
  • Basic algebra skills for unit conversion and solving equations.
NEXT STEPS
  • Review the concept of gravitational acceleration at different altitudes.
  • Study the principles of orbital mechanics and satellite motion.
  • Learn about the derivation and application of the formula a = v²/r.
  • Practice solving problems involving satellite velocity and altitude adjustments.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and orbital dynamics, as well as educators looking for examples of satellite motion calculations.

zade70
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Homework Statement


An object stand in the height 500km from the surface of the Earth. What velocity should it have to become an Earth satellite?

Homework Equations


a=v2/r

The Attempt at a Solution


v2=a*r=6,9*107=>x=8306m/S , but the solution is 7600m/S
 
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What's a? What's r? Watch units and you got your algebra wrong.
 
And what is x?

I would expect an error at the value of "a" you used.
 

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