Find the voltage across the resistor

[ooohffff]

Homework Statement

A battery with

= 12.0 V and internal resistance r = 1.0 Ω is connected to two 6.9 kΩ resistors in series. An ammeter of internal resistance 0.50 Ω measures the current, and at the same time a voltmeter with internal resistance 10.0 kΩ measures the voltage across one of the 6.9 kΩ resistors in the circuit. What do the ammeter and the voltmeter read?

Homework Equations

V=IR

The Attempt at a Solution

So I found the ammeter reading where I_total=1.09mA which was correct.
For the voltmeter reading, I got:
V=I_total*6.9kΩ=7.52V which was incorrect. Anyone care to help?

 

[phinds]

Anyone care to help?

Help what? You haven't shown any work, just answers. That's not the way it works here.

 

[ooohffff]

Help what? You haven't shown any work, just answers. That's not the way it works here.

Ammeter reading:
R_parallel=[(1/6.9k)+(1/10k)]^-1=4082.84
R_total= 6.9kΩ+4082.84Ω+1Ω+.5Ω=10984.34Ω
I_total=V/R=12/10984.34=.00109A

Better?

 

[ooohffff]

Ah, I got it it's V=I_totalR_parallel