1. The problem statement, all variables and given/known data Determine the voltage drop across R1 R1 = 770 , R2 = 630 , and R3 = 470 . The equivalent resistance is 816Ω 2. Relevant equations V = IR 3. The attempt at a solution 1.) I find the total current of the circuit: V = IR -> I = V/R I = 12v/816Ω = 0.015A 2.) I then find the voltage drop across that particular resistor: V = IR V = 0.015A * 770Ω V = 11.32v This has been confirmed to be the wrong answer. I don't understand what I am doing incorrectly. Could someone please help me understand my mistake (where ever it may be)? Many Thanks!