Find the volume of the ellipsoid

  • Thread starter Thread starter Whatupdoc
  • Start date Start date
  • Tags Tags
    Ellipsoid Volume
Click For Summary
SUMMARY

The volume of the ellipsoid defined by the equation x² + y² + 10z² = 16 can be calculated using the integral V = 4π ∫(from 0 to 4√5/5) ∫(from 0 to √(16 - 10z²)) r dr dz. The correct formula for the volume of an ellipsoid is V = (4/3)πabc, where a, b, and c are the semi-axis lengths. The discussion highlights the importance of setting up volume integrals correctly to avoid errors in calculations.

PREREQUISITES
  • Understanding of ellipsoids and their equations
  • Familiarity with double integrals in calculus
  • Knowledge of polar coordinates and transformations
  • Experience with volume calculations in multivariable calculus
NEXT STEPS
  • Study the derivation of the volume formula for ellipsoids: V = (4/3)πabc
  • Learn about setting up double integrals in polar coordinates
  • Practice solving volume integrals with different geometric shapes
  • Explore applications of volume integrals in physics and engineering
USEFUL FOR

Students and professionals in mathematics, particularly those focusing on calculus and geometry, as well as educators teaching volume calculations and integral setups.

Whatupdoc
Messages
99
Reaction score
0
Find the volume of the ellipsoid x^2 + y^2 + 10z^2 = 16
solve for z... z=sqrt((16-x^2-y^2)/(10))
z = sqrt((16-r^2)/10)
so to find the volume, my integral looks like this:

latex doesn't seem to be working, so this could look messy...

2*int (from 0-2pi)*int(from 0-1)* sqrt((16-r^2)/(10))*r*dr*d(theta)

the 2 in front of the integral is to find the volume, since the integral only gives half of the volume right? is my setup correct? cause i keep getting the wrong answers
 
Physics news on Phys.org
Your setup looks okay. I would have set it up this way:

V = 4\pi \int_{0}^{4\sqrt{5}/5} \int_{0}^{\sqrt {16-10z^2}} r dr dz
 
The volume of the ellipsoid \left(\frac{x}{a}\right)^{2}+\left(\frac{y}{b}\right)^{2}+\left(\frac{z}{c}\right)^{2}=1 is V=\frac{4\pi}{3}abc.
 
benorin said:
The volume of the ellipsoid \left(\frac{x}{a}\right)^{2}+\left(\frac{y}{b}\right)^{2}+\left(\frac{z}{c}\right)^{2}=1 is V=\frac{4\pi}{3}abc.

I think the point was learning how to do volume integrals! Just a guess. :smile:
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
Replies
4
Views
3K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
9
Views
10K