Find the volume of the hexagonal-shaped plastic box

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SUMMARY

The discussion centers on calculating the volume of a hexagonal-shaped plastic box used to pack 24 triangular chocolate bars. Each chocolate bar has a base length of 3 cm and base angles of 50 degrees, with the height represented as h cm. To find the volume of the hexagonal box, one must first determine the volume of a single triangular chocolate bar, which involves calculating the height using the formula h = (3/2)tan(50°). The volume of the box is then the product of the volume of one chocolate bar and 24.

PREREQUISITES
  • Understanding of geometric volume calculations
  • Knowledge of trigonometric functions, specifically tangent
  • Familiarity with the properties of isosceles triangles
  • Basic knowledge of hexagonal geometry
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  • Calculate the height of the triangular chocolate bar using h = (3/2)tan(50°)
  • Determine the volume of a single triangular chocolate bar
  • Research the formula for the volume of a hexagonal prism
  • Explore packing efficiency for hexagonal shapes in packaging design
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Mathematicians, packaging engineers, and anyone involved in product design or geometry who needs to calculate volumes for irregular shapes.

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A chocolate company produces triangular chocolate bars. The length of the chocolate bar is x cm, and its cross section is an isosceles triangle. The length of the base side of the cross section is 3 cm, the height is h cm, and the two base angles are 50 degrees.
View attachment 9689

Moreover, the company uses a hexagonal-shaped plastic box to pack 24 chocolate bars together as shown in the figure below.
View attachment 9690

What is the volume of the hexagonal-shaped plastic box?

*I would like to apologize if I keep on editing the content of my problem. Originally, the question asked was to find the volume of the hexagonal shaped plastic box. In my opinion, I can only solved this if I will be able to find the volume of each triangular chocolate bars then multiply it by 24 (please correct me if my view was invalid). However, I am really having a hard time in solving for x.
 

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Is it asking you for the height of the chocolate bar, or the side length?

Have you drawn a diagram?
 
$h = \dfrac{3}{2}\tan(50^\circ)$

You’ll need the bar’s volume to determine the length of the bar, $x$.
 
*I would like to apologize if I keep on editing the content of my problem. Originally, the question asked was to find the volume of the hexagonal shaped plastic box. In my opinion, I can only solved this if I will be able to find the volume of each triangular chocolate bars then multiply it by 24 (please correct me if my view was invalid). However, I am really having a hard time in solving for x.

What measurement information was given about the hexagonal box? As it sits, there is not enough information to determine $x$.
 
angubk6 said:
*I would like to apologize if I keep on editing the content of my problem. Originally, the question asked was to find the volume of the hexagonal shaped plastic box. In my opinion, I can only solved this if I will be able to find the volume of each triangular chocolate bars then multiply it by 24 (please correct me if my view was invalid). However, I am really having a hard time in solving for x.

Post the entire problem to start with, with everything you have tried, and then we can actually help you!
 

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