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Find the volume of the solid revolved around a region

  1. Dec 10, 2012 #1
    1. The problem statement, all variables and given/known data
    Find the volume of the solid generated by revolving the region bounded by the graphs of y2=4x, the line y=x, about
    A) x=4
    B) y=4


    So first I start out by graphing it
    FwU0Q.png

    The intercepts are at 0,0 and 4,4

    I use the washers method since there is a gap in between the line and the rotated solid, making a space in the middle of the solid

    The washers method says V= ∏∫ ([R(x)]2 - [r(x)2) where R(x) is the largest(outer) area, and r(x) is the smallest(inside) area. This is for rotating about the x axis but can be used to rotate around the y axis. However, this isn't rotating about either of these axis; rather, it's rotating around x=4 which is what I am having trouble with.

    So boundaries are 0 to 4, equation is ∏∫([y2/4]2 - y2)dy but this is wrong. How would I do it correctly? Is cylindrical shells a better method? If I was using cylindrical shells, would it be 2∏∫(2√x - x)(x) since I use ∫ 2∏(shell height)(shell radius) Also I'm a bit confused on how I would do part B

    Any help would be great, thanks.
     
    Last edited: Dec 10, 2012
  2. jcsd
  3. Dec 10, 2012 #2
    For part B, also using the cylindrical shells method, would the proper integral be 2∏∫(y - y2/4)(y)
     
  4. Dec 10, 2012 #3

    Dick

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    Nice picture. For the first one, if you are rotating around x=4, then wouldn't the inner radius be 4-y and the outer radius be 4-y^2/4? The radii should be distances to the axis of rotation.
     
  5. Dec 10, 2012 #4
    Ah I see, that makes sense, thank you. Is what I posted above (2∏∫(2√x - x)(x) for x=4, 2∏∫(y - y2/4)(y) for y=4) correct for cylindrical shell method?
     
  6. Dec 10, 2012 #5

    Dick

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    Same problem. I think you have the lengths of the shells right, but you don't have the radius right. You aren't rotating around 0.
     
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