- #1
maverick280857
- 1,789
- 4
Hi,
I'm teaching myself quantum mechanics (so this isn't homework). I came across the following question:
[tex]\Phi(p) = A\Theta\left[\frac{\hbar}{d}-|p-p_{0}|\right][/tex]
I have to find the constant of normalization, [itex]\psi(x)[/itex], and the coordinate space wave function [itex]\psi(x,t)[/itex] in the limit [itex]\frac{h/d}{p_{0}} << 1[/itex].
I started by finding [itex]A[/itex]:
[tex]\int_{-\infty}^{\infty}\frac{|\Phi(p)|^2}{2\pi\hbar}dp = 1[/tex]
This gives [itex]A = \sqrt{\pi d}[/itex].
Now,
[tex]\psi(x) = \frac{1}{2\pi\hbar}\int_{-\infty}^{\infty}dp'\Phi(p')e^{-ip'x/\hbar}[/tex]
which gives
[tex]\psi(x) = \sqrt{\frac{d}{\pi}}e^{ip_{0}x/\hbar}\frac{\sin(x/d)}{x}[/tex]
(There may be an algebraic error here..)
My problem is: how do I find [itex]\psi(x,t)[/itex]? I am not sure how to proceed here.
I'm teaching myself quantum mechanics (so this isn't homework). I came across the following question:
[tex]\Phi(p) = A\Theta\left[\frac{\hbar}{d}-|p-p_{0}|\right][/tex]
I have to find the constant of normalization, [itex]\psi(x)[/itex], and the coordinate space wave function [itex]\psi(x,t)[/itex] in the limit [itex]\frac{h/d}{p_{0}} << 1[/itex].
I started by finding [itex]A[/itex]:
[tex]\int_{-\infty}^{\infty}\frac{|\Phi(p)|^2}{2\pi\hbar}dp = 1[/tex]
This gives [itex]A = \sqrt{\pi d}[/itex].
Now,
[tex]\psi(x) = \frac{1}{2\pi\hbar}\int_{-\infty}^{\infty}dp'\Phi(p')e^{-ip'x/\hbar}[/tex]
which gives
[tex]\psi(x) = \sqrt{\frac{d}{\pi}}e^{ip_{0}x/\hbar}\frac{\sin(x/d)}{x}[/tex]
(There may be an algebraic error here..)
My problem is: how do I find [itex]\psi(x,t)[/itex]? I am not sure how to proceed here.