Find the work done by a spring using potential energy considerations

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SUMMARY

The discussion focuses on calculating the work done by a spring using potential energy considerations, specifically through the equation W = F*S and the elastic potential energy formula U = 1/2kx^2. Participants debated whether to add or subtract the potential energies U1 and U2 when transitioning from -x to +x. Key points include understanding that at x=0, the spring is neither compressed nor stretched, and the change in elastic potential energy (EPE) is determined by the difference between the final and initial states of the spring.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants (k)
  • Familiarity with the concept of elastic potential energy (EPE)
  • Knowledge of work-energy principles in physics
  • Ability to manipulate algebraic equations involving potential energy
NEXT STEPS
  • Study the derivation and applications of Hooke's Law in various contexts
  • Learn about the relationship between work done and energy conservation in mechanical systems
  • Explore advanced topics in potential energy, including gravitational and elastic potential energy comparisons
  • Investigate real-world applications of springs in engineering and physics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy concepts, as well as educators seeking to clarify spring dynamics and potential energy calculations.

good jelly
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Homework Statement
Find the work done by spring from -x to x
Relevant Equations
W=FS U=1/2kx^2
At first I tried using U1 = 1/2kx^2 from -x to zero then U2 from zero to +x but I don't know shall I add U1 and U2 or subtract them?
 
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Does x=0 imply the spring Isn't compressed ir stretched?
 
good jelly said:
Homework Statement: Find the work done by spring from -x to x
Relevant Equations: W=FS U=1/2kx^2

At first I tried using U1 = 1/2kx^2 from -x to zero then U2 from zero to +x but I don't know shall I add U1 and U2 or subtract them?
Which is reasonable do you think ?
 
@good jelly, remember that x is the spring’s length minus it natural (unloaded) length.

Can you answer the following questions?

1. In the initial state (‘-x’), is the spring extended or compressed?

2. What is the value of the elastic potential energy (EPE) in the initial state?

3. Does the EPE increase or decrease going from the initial state to the unloaded (x=0) state? By how much?

4. In the final state (‘+x’), is the spring extended or compressed?

5. What is the value of the EPE in the final state?

6. Does the EPE increase or decrease going from the unloaded (x=0) state to the final state? By how much?

7. Considering your answers to Q3 and Q6, what is the overall change in EPE?

Minor edit.
 
Last edited:
By definition, the change in potential energy from point A to point B is the negative of the work done by the conservative force on the system from point A to point B.

Can you find the potential energy change when the spring is stretched from -x to +x? Hint: Change is final value minus initial value.
 
Last edited:

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