# Find the x coordinate of the stationary point of the following curves

## Homework Statement

Find dy/dx and determine the exact x coordinate of the stationary point for:

(a) y=(4x^2+1)^5

(b) y=x^2/lnx

## The Attempt at a Solution

(a) y=(4x^2+1)^5

dy/dx=40x(4x^2+1)^4

40x(4x^2+1)^4=0

Find x... How?

(b) y=x^2/lnx

dy/dx=2xlnx-x^2 1/x / (lnx)^2

2xlnx-x^2 1/x / (lnx)^2=0

Find x... How?

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40x(4x^2+1)^4=0

Find x... How?
re 1st prob:

Then either 40x = 0 or (4x^2+1)^4 = 0.

and solve the above two equations.

HallsofIvy
You are aware that $x^2/x= x$ aren't you?
$y= x^2/ln(x)$: $y'= (2xln(x)- x)/(ln(x))^2= 0$
Use parentheses! What you wrote was $y'= 2x ln(x)- (x/(ln(x))^2)= 0$.
Multiply both sides of the equation by $(ln(x))^2$