- #1

Lo.Lee.Ta.

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2. So I thought the first step would be to find the slope of the tangent line.

I think we find the slope of the tangent line by taking the derivative.

So I am going to use the Quotient Rule to take the derivative.

[(√3 + x)(0) - (-.4)(.5(x + 3)^-1/2) * 1] / √(x + 3)^2

.2√(x + 3) / (x + 3)

**<-----**This is the slope of the tan line to y= -.4/√(3 + x)

If we want to know the slope at x = 2.5, then wouldn't we plug in 2.5 for x?

So, [.2√(3 + 2.5)]/(2.5 + 3) = .085

**<-----**This is the slope

Now, I thought we could substitute everything into y = mx + b in order to find out what b is.

-.1705606 = .085(2.5) + b

b = -.3831

3. But this is NOT the right answer!

Please tell me what I am doing wrong!

Thank you! :)