Find Thermal Energy & Initial Speed of Skidding 1200kg Car

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SUMMARY

The discussion focuses on calculating the thermal energy and initial speed of a 1200 kg car skidding with a coefficient of friction (uk) of 0.45 over a distance of 45.2 meters. The frictional force (Ff) is determined to be 5292 N, leading to a work done (thermal energy) of 239198.4 J. However, the textbook indicates the thermal energy should be 5.3 kJ and the initial speed 72 km/h. The discrepancy arises from the understanding that the work done equals the loss in kinetic energy, which is converted to thermal energy during skidding.

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bigmac
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Homework Statement



A 1200kg car skids with uk = 0.45. If it skids 45.2m, find the thermal energy and the initial speed.

m = 1200 kg
Vi = ?
Vf = 0 m/s (i think..because it wants to stop)
uk = 0.45 (coefficient of friction)
delta d = 45.2m

Homework Equations



Well for Frictional force we use Ff = uk x Fn (0.45x11760) = 5292N


The Attempt at a Solution



So I found the Fn which is 1200 x 9.8 = 11760 N

Then I found Ff which is 0.45 x 11760 = 5292 N

Then I found the work done (I don't know why thermal energy is the work can someone explain this please)

W = F x d = 5292 x 45.2 = 239198.4 J

But my textbook's answer key has a different answer for the thermal energy, it says it should be 5.3 kJ and 72km/h for the speed. How do we find the speed?
 
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bigmac said:
I don't know why thermal energy is the work can someone explain this please

Hi bigmac! :smile:

work done = loss in energy (the work-energy equation), and nearly all the energy lost is thermal. :wink:

So they're different things, but they're equal in value.

And once you have the thermal energy, you can equate it to ∆(KE) :smile:
… W = F x d = 5292 x 45.2 = 239198.4 J

But my textbook's answer key has a different answer for the thermal energy, it says it should be 5.3 kJ and 72km/h for the speed. How do we find the speed?

Are you sure it doesn't say 5.3 kN ? :confused:

Using your figure for W, I do get 72km/h for the speed.
 

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