Find this limit without L'Hopital's Rule

Click For Summary
SUMMARY

The limit lim (sqrt(x)/sqrt(sin(x))) as x approaches 0 from the positive side can be evaluated without L'Hopital's Rule by utilizing the power series expansion of sin(x). Specifically, the relevant limit is lim_{x -> 0} (sin(x)/x) = 1, which aids in simplifying the expression. The solution involves recognizing that as x approaches 0, sin(x) can be approximated by its Taylor series expansion, leading to a definitive evaluation of the limit.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with Taylor series expansions
  • Knowledge of the properties of sine function
  • Ability to manipulate algebraic expressions
NEXT STEPS
  • Study Taylor series expansion for sin(x) and its applications
  • Learn about alternative limit evaluation techniques beyond L'Hopital's Rule
  • Explore the concept of continuity in functions and its implications for limits
  • Review the properties of square roots in calculus
USEFUL FOR

Students of calculus, mathematics educators, and anyone looking to deepen their understanding of limit evaluation techniques without relying on L'Hopital's Rule.

htoor9
Messages
16
Reaction score
0

Homework Statement



L'Hopital's rule does not help with this limit. Find it some other way. lim (squarert(x)/squarert(sinx)) as x -> 0+

Homework Equations



None?

The Attempt at a Solution



The only way I can think of solving this is by using L'Hopital's rule...but it obviously isn't working. How else can I find this limit?
 
Physics news on Phys.org
htoor9 said:

Homework Statement



L'Hopital's rule does not help with this limit. Find it some other way. lim (squarert(x)/squarert(sinx)) as x -> 0+

Homework Equations



None?
There are at least a couple of limits that are relevant.
[tex]\lim_{x \to 0} \frac{sin(x)}{x} = 1[/tex]
[tex]\lim_{x \to a} f(g(x)) = f(\lim_{x \to a} g(x)), \text{provided that f is continuous at g(a)}[/tex]
htoor9 said:

The Attempt at a Solution



The only way I can think of solving this is by using L'Hopital's rule...but it obviously isn't working. How else can I find this limit?
 
Expand sin x as a power series...
 

Similar threads

Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 23 ·
Replies
23
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 21 ·
Replies
21
Views
7K
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
2K