Find Time: Solving Kinematic Equations for Baseball Motion

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SUMMARY

The discussion focuses on solving kinematic equations to determine the time a baseball takes to pass a window and return to the street after being thrown. The baseball reaches a height of 25 meters with an initial vertical speed of 13 m/s, and the initial velocity calculated is 25.67 m/s. The participant successfully calculated the time to pass the window as 2.6 seconds but struggled with determining the total time until the ball returns to the street. The relevant kinematic equations discussed include v = v0 + at and d1 = d0 + vt + (1/2)at².

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czlu
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sorry, i meant how to find TIME.

Homework Statement


A baseball is seen to pass upward by a window 25 m above the street with a vertical speed of 13 m/s. The ball was thrown from the street. I figured out the altitude thrown was 33.62 and the initial velocity was 25.67.

(a) How long after it was thrown did it pass the window?

(b) After how many more seconds does it reach the street again?

Homework Equations


the 4 kinematic equations

For example, v^2=v0^2+2a(x-x0)

The Attempt at a Solution


I tried V=V0+at
and and got 2.6 for part a and have no clue how to do part b. can someone help me out?
 
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Not sure how you arrived at 2.6 for part a. I'd check that.

For part b, you know that the final vertical distance is zero and you have worked out the initial velocity. Which kinematic equation has distance initial velocity and time in it?
 
correct me if I am wrong d1=d0+vt+(1/2)a(t2)

that's all you need isn't it?
 

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