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Find time to reach ball. 1D motion

  1. Jan 31, 2013 #1
    1. The problem statement, all variables and given/known data

    basket ball player throws a ball up in the air and the ball travels 3.2meters before stopping. if the basketball player jumps .5 seconds after throwing the ball. what velocity does he need to reach the ball.

    2. Relevant equations

    vf^2=v1^2+2as
    sf=si+vot+1/2at^2
    vf=vi+aot

    3. The attempt at a solution

    i use vf^2=vo^2+2as to solve for the initial velocity of the ball which i get 7.919 m/s . I solve for the time it takes the ball to reach the max height by using vf=vi+aot and i get .808 seconds. I have no idea had to solve then for the basketball player? Do i use the same method as the ball and if i do; what do i do with the .5 second delay?
     
    Last edited: Jan 31, 2013
  2. jcsd
  3. Jan 31, 2013 #2

    tms

    User Avatar

    I assume that the point is for the player to reach the the highest point of the ball's trajectory at the same time as the ball does.

    You have found how long the ball takes to reach that point, and you are told the delay. The player must reach the same point in the same time, starting after the delay. Use the same method as before to find the player's motion. I don't know what you are supposed to do about the player's height.

    It is best to quote the problem exactly instead of paraphrasing, because some vital information might get left out or unintentionally misstated.
     
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