Find Torque of Circle Homework Solution

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minikk
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Homework Statement



A Circular-shaped object has an inner radius of 12 cm and an outer radius of 20 cm. Three forces (acting perpendicular to the axis of rotation) of magnitudes 11 N, 28N, and 16 N act on the object. The force of magnitude 28 N acts 29 degrees below the horizontal. Find the magnitude of the net torque through the center of the object.

torque.jpg


Homework Equations

The Attempt at a Solution


So I added all the torques together.
-(.12*28)+(.2*11)+(.2*16)=2.04
which came out to 2.04 Nm. Am I right? When I put it, it said it was wrong...
 
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Hi minikk, welcome to PF.
From the diagram I feel that the force 28 N may not be perpendicular to the radius of the smaller circle. That is why they have given the angle of the force below the horizon.