Finding the mass of a ball and a rod using torque

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Homework Help Overview

The discussion revolves around a physics problem involving a rod with its center of mass labeled and a ball hanging from it, attached by a string. Participants are tasked with finding the masses of both the ball and the rod using the concept of torque, with a diagram referenced but not provided.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to calculate torque by designating the center of mass of the rod as the axis and applying the torque formula. They express confusion over obtaining a negative torque value for the ball's weight while another torque appears positive. Some participants question the clarity of the problem setup, including the directions of the torques and the equilibrium state of the system. Others suggest that the forces acting on the rod are causing rotations and inquire about the support structure of the rod.

Discussion Status

Participants are actively questioning the assumptions and details of the problem, noting the ambiguity of the setup without a diagram. Some have pointed out the need for clarity regarding the forces and torques involved, while others emphasize the importance of understanding the system's equilibrium. Guidance has been offered regarding the interpretation of forces and torques, but no consensus has been reached on how to proceed without additional information.

Contextual Notes

There is a noted lack of clarity regarding the diagram, the exact positions of forces, and whether the system is in equilibrium. Participants are also discussing the implications of having an upward force acting on the rod, which complicates the ability to determine the masses involved.

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Homework Statement


There is a diagram of a rod with its center of mass labeled and a ball hanging down from it, attached by a string. Two torques are applied on either side. You are asked to find the mass of the ball and the mass of the rod.

Homework Equations


Torque = Force * Lever Arm * sine of angle between them

The Attempt at a Solution


I designated the center of mass of the rod as the axis, and then calculated the torque applied by each force by multiplying the magnitude of the force by the distance between where the force was applied and the center of mass of the rod. There is an angle of 60 degrees on the other side of where one force is being applied, so I calculated that the angle between the force and r (the lever arm, or distance from where that force is applied to the center of mass of the rod) is 120 degrees by subtracting 60 degrees from 180 degrees. What confuses me, though, is that, when I did my calculations, I got a negative value for the torque resulting from the ball's weight. I know torque can be negative, since it is a vector, but what confuses me about this result is that there is another torque that appears to be acting in the same direction as the one caused by the weight of the ball, yet it is positive. So I must have done something wrong. What is it?

Here are my calculations:

9N * 0.09m = 0.81 Nm

5.02N * sin120 degrees * 0.06m = 0.260846852 Nm

0.81 + Tball = 0.260846852

This is where I got the negative result.
 
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There's a lot of information missing here.
Physics Person said:
There is a diagram of a rod with its center of mass labeled and a ball hanging down from it, attached by a string. Two torques are applied on either side.
On either side of what? What direction are the torques? What do we know besides the fact that the torques are acting on it? Is this system in equilibrium? Where is the ball hanging relative to the center of mass? Where is the center of rotation relative to the center of mass and the ball?

Please attach a picture.
 
The two torques are applied on either end of the rod. It is not specified explicitly whether the system is equilibrium, but it appears to be in equilibrium from the picture. The torques appear to be pushing down on the rod. The ball is seven centimeters from the center of mass. You're supposed to treat a different position as the center of rotation, depending on whether you are trying to find the mass of the ball or the mass of the rod. When I was trying to find the mass of the ball, I treated the center of mass of the rod as the center of rotation. When I try to find the mass of the rod, I guess I'll just pick another point to be the center of rotation -- maybe where the ball is.
 
Physics Person said:
The torques appear to be pushing down on the rod.
Do you mean that two forces push down on the rod, and these will generate torques?
You describe a ball "hanging" from the rod, so I assume this is in a vertical plane and subject to gravity. Is there anything supporting the rod? Can't be in equilibrium if not!

Edit: maybe they are applied torques, not forces, but in that case it makes no sense to say they push down on the rod. They exert clockwise or anticlockwise torques. These could balance the torques produced by the weights of ball and rod, but still will not lead to equilibrium without an upward force somewhere.
 
to repeat @RPinPA ' s requst, please post the diagram. The question seems to be ambiguous without more details.
 
Yes, the rod is shown hanging from something else in the picture. Yes, the ball hanging from the rod is in a vertical plane and, I presume, therefore is subject to gravity. And the magnitudes of the applied forces are given in Newtons, hence why I referred to them as forces. They are forces that tend to cause a rotation. The one on the left seems like it would cause a counterclockwise rotation, whereas the one on the right seems like it would cause a clockwise rotation (assuming the axis of rotation to be the center of mass of the rod, which, in the picture, is shown to be pretty much right smack-dab in the center of the rod).
 
Physics Person said:
Yes, the rod is shown hanging from something else in the picture. Yes, the ball hanging from the rod is in a vertical plane and, I presume, therefore is subject to gravity. And the magnitudes of the applied forces are given in Newtons, hence why I referred to them as forces. They are forces that tend to cause a rotation. The one on the left seems like it would cause a counterclockwise rotation, whereas the one on the right seems like it would cause a clockwise rotation (assuming the axis of rotation to be the center of mass of the rod, which, in the picture, is shown to be pretty much right smack-dab in the center of the rod).
If there is a single support in the centre of the rod, providing an unknown upward force, it will be impossible to find the mass of the rod.
I can't see that we will get very far with this until you attach an image of the problem as given to you.
 
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haruspex said:
If there is a single support in the centre of the rod, providing an unknown upward force, it will be impossible to find the mass of the rod.
I can't see that we will get very far with this until you attach an image of the problem as given to you.

I cannot figure out how to insert an image, since, when I click on the image icon when I am typing out my reply, it asks for the URL of the image, and I do not have the image uploaded to any website, but instead have it saved among the images on my phone.
 
Physics Person said:
I cannot figure out how to insert an image, since, when I click on the image icon when I am typing out my reply, it asks for the URL of the image, and I do not have the image uploaded to any website, but instead have it saved among the images on my phone.
See the UPLOAD button, lower right.
 

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