Find v(z) given volume charge density

In summary, the problem involves finding v(z) for a parallel plate capacitor with plates separated by a distance d and with a given volume charge density ρ_v. Using the equation ρ_v = ρ_o*sin(pi*z/2*d), the solution involves taking the definite integral of ρ_v with respect to z, which results in v(z) = -ρ_o*(2d/pi)^2*sin(pi*z/2*d) +Az + B. To solve for the integration constants A and B, definite integrals must be used and an ε0 term may also be missing.
  • #1
derek l

Homework Statement


Consider the parallel plate capacitor(no figure). The capacitor plates have a separation distance d in the z-direction. The volume charge density is given by ρ_v. Find v(z).

Homework Equations


ρ_v = ρ_o*sin(pi*z/2*d)

The Attempt at a Solution


[/B]
∫(ρ_vdz) = -ρ_o*2d/pi*cos(pi*z/2*d) +A= dv/dz

∫dv/dz = -ρ_o*(2d/pi)^2*sin(pi*z/2*d) +Az + B = v(z)
 
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  • #2
You need to consider definite integrals so that the integration constants can be defined. What are your limits of integration? Also, it looks like you are missing an ε0 somewhere.
 

1. What is the formula for finding v(z) given volume charge density?

The formula for finding v(z) given volume charge density is v(z) = ∫ρ(z) dz, where ρ(z) is the volume charge density and ∫ is the integral of the function over the given range.

2. How do you determine the volume charge density for a given system?

The volume charge density can be determined by dividing the total charge of the system by its volume. This can be written as ρ = Q/V, where Q is the total charge and V is the volume of the system.

3. Can v(z) be negative or zero?

Yes, v(z) can be negative or zero. This depends on the distribution of the volume charge density and the range of the integral. If the volume charge density is negative over the given range, the value of v(z) will also be negative.

4. How does the value of v(z) change with respect to the range of the integral?

The value of v(z) will change depending on the range of the integral. If the range is increased, the value of v(z) will also increase, and vice versa. This is because a larger range means a larger volume of charge is being integrated, resulting in a higher value for v(z).

5. Is there a specific unit for volume charge density?

Yes, the unit for volume charge density is coulombs per cubic meter (C/m^3). This unit is derived from the SI unit for charge (coulombs) and the SI unit for volume (cubic meters).

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