Find Volume of Revolution for y=2+x and y=x^2 about y-axis | Shell Method

  • Thread starter Thread starter miz_ai
  • Start date Start date
  • Tags Tags
    Revolution Volume
Click For Summary
SUMMARY

The volume of revolution for the area bounded by the equations y=2+x and y=x^2 about the y-axis can be calculated using the shell method. The integral to find this volume is expressed as ∫(0 to 2) x(2+x-x^2) dx. The discussion highlights a debate regarding whether to include the left part of the solid in the volume calculation, with a consensus leaning towards focusing on the region where x is greater than 0 for clarity and accuracy.

PREREQUISITES
  • Understanding of the shell method for calculating volumes of revolution
  • Familiarity with integral calculus, specifically definite integrals
  • Knowledge of the equations of curves and their intersections
  • Ability to interpret and manipulate algebraic expressions
NEXT STEPS
  • Study the shell method in detail, focusing on its application to volumes of revolution
  • Learn how to set up and evaluate definite integrals for various functions
  • Explore the concept of bounded regions and their significance in volume calculations
  • Investigate the differences between rotating around the y-axis versus the x-axis
USEFUL FOR

Students studying calculus, particularly those focusing on volumes of revolution, as well as educators seeking to clarify concepts related to the shell method and integral calculus.

miz_ai
Messages
1
Reaction score
0

Homework Statement


Find the volume generated by rotating the area bounded by y=2+x and y=x^2 about the y-axis.


Homework Equations


Volume of revolution.

The Attempt at a Solution


shell method
integral (0 to 2) of x(2+x-x^2) dx

I think this can be solved by eliminating the left part and only count the volume of the left side, because the left part of the solid result is covered by the right part. It's a problem in my school because our teacher is debating whether the left part is counted or not.

i'm sorry i can't write in equotion.. I'm newbie
 
Physics news on Phys.org
IF the problem really says "rotate around the y-axis, then you are right: the solid is generated is by the region between y= x+ 2 and y= x2 for x> 0. The problem would make more sense and be more interesting if it were rotated around the x-axis.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
3
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
2
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 16 ·
Replies
16
Views
5K
Replies
1
Views
2K